A light wave travels through water (n=1.33) at an angle of 35º. What angle

Physics

2 answers:

san4es73 [151]3 years ago

6 0

Answer:

$49.7^{\circ}$

Explanation:

We can solve the problem by using Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

$\theta_1 = 35^{\circ}$ is the angle of incidence of the wave in water

$\theta_2$ is the angle of refraction of the wave in air

Solving for the angle of refraction,

$sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}$

fiasKO [112]3 years ago

3 0

Answer:

49.7

Explanation:

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