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3 years ago

A light wave travels through water (n=1.33) at an angle of 35º. What angle

Physics

2 answers:

san4es73 [151]3 years ago

6 0

Answer:

$49.7^{\circ}$

Explanation:

We can solve the problem by using Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

$\theta_1 = 35^{\circ}$ is the angle of incidence of the wave in water

$\theta_2$ is the angle of refraction of the wave in air

Solving for the angle of refraction,

$sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}$

fiasKO [112]3 years ago

3 0

Answer:

49.7

Explanation:

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3 years ago

Brainliest please help tell me if am right if not correct me please

REY [17]

Answer:

See the answers below

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f}=v_{o}+a*t$

where:

Vf = final velocity [m/s]

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a = acceleration [m/s²]

t = time [s]

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t = 2 [s]

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Second case

Vf = 25 [m/s]

Vo = 5 [m/s]

a = 2 [m/s²]

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Third case

Vo =4 [m/s]

a = 10 [m/s²]

t = 2 [s]

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Fourth Case

Vf = final velocity [m/s]

Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

$v_{f}=5+8*10\\v_{f}=85 [m/s]$

Fifth case

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Vo = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

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3 years ago

Two identical asteroids travel side by side while touching one another. If the asteroids are composed of homogeneous pure iron a

victus00 [196]

Answer:

diameter = 21.81 ft

Explanation:

The gravitational force equation is:

$F=\frac{GMm}{R^{2} }$

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F => Gravitational force or force of attraction between two masses
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We also know that the asteroids are identical so their masses are identical:

Since R is the distance between centers of the two asteroids and their diameters are identical (see attachment), we can conclude that:

R=d=2r

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This is going to be helpful because the volume of a sphere is:

$\frac{4}{3}\pi r^{3}$

And know we can write our original force of gravity equation in terms of the radius of the asteroids:

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