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liraira [26]
3 years ago
7

A light wave travels through water (n=1.33) at an angle of 35º. What angle

Physics
2 answers:
san4es73 [151]3 years ago
6 0

Answer:

49.7^{\circ}

Explanation:

We can solve the problem by using Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

\theta_1 = 35^{\circ} is the angle of incidence of the wave in water

\theta_2 is the angle of refraction of the wave in air

Solving for the angle of refraction,

sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}

fiasKO [112]3 years ago
3 0

Answer:

49.7

Explanation:

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EMERGENCY! PLEASE HELP!
hichkok12 [17]

Answer: Volume = 1080m^3

Explanation:

Given that the prism has a 15 m by 18 m rectangular base and a height of 4 m

Volume is the product of length, breath and height. That is

Volume = L × B × H

Where

L = 18 m

B = 15m

H = 4m

Using the formula above gives:

Volume V = 18 × 15 × 4

V = 1080 m^3

8 0
3 years ago
calculate the force required to take away a flat corcular plate of radius 0.01m from the surface of water. the surface tention o
leonid [27]

Answer:

Force = 0.0047175\ N

Explanation:

Given

T = 0.075N/m --- Surface Tension

r = 0.01m --- Radius

Required

Determine the required force

First, we calculate the circumference (C) of the circular plate

C= 2\pi r

C= 2 * \frac{22}{7} * 0.01m

C= \frac{2 * 22 * 0.01}{7}m

C= \frac{0.44}{7}m

C= 0.0629 m

The applied force is then calculated using;

Force = C * T

Force = 0.0629m * 0.075N/m

Force = 0.0047175\ N

8 0
3 years ago
The earth has a radius of 6.38 × 106 m and turns on its axis once every 23.9 h.
Vladimir [108]

Answer:

a) V = 465.9 m/s

b) θ = 70.529°

Explanation:

Let's first calculate angular velocity of earth:

\omega=\frac{2\pi}{23.9h}*1h/3600s

Velocity of a person on Ecuador will be:

V_E = \omega*R

V_E = 465.9 m/s

For part b, since angular velocity is the same:

\frac{\omega*R}{3}=\omega*(R*cos\theta )

Solving for θ:

\theta=acos(1/3)

\theta=70.529\°

8 0
3 years ago
A cart is driven by a large propeller or fan, which can accelerate or decelerate the cart. The cart starts out at the position x
mash [69]

Answer:

The acceleration of the cart is 1.0 m\s^2 in the negative direction.

Explanation:

Using the equation of motion:

Vf^2 = Vi^2 + 2*a*x

2*a*x = Vf^2 - Vi^2

a = (Vf^2 - Vi^2)/ 2*x

Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.

Let x = Xf -Xi

Where Xf is the final position of the cart and Xi the initial position of the cart.

x = 12.5 - 0

x = 12.5

The cart comes to a stop before changing direction

Vf = 0 m/s

a = (0^2 - 5^2)/ 2*12.5

a = - 1 m/s^2

The cart is decelerating

Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.

5 0
3 years ago
When two pool balls collide, what happens to the momentum of each one?
Schach [20]

Answer:

They slow down.

Explanation:

The collided so the slow down till they stop.

7 0
3 years ago
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