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3 years ago

A light wave travels through water (n=1.33) at an angle of 35º. What angle

Physics

2 answers:

san4es73 [151]3 years ago

6 0

Answer:

$49.7^{\circ}$

Explanation:

We can solve the problem by using Snell's law:

$n_1 sin \theta_1 = n_2 sin \theta_2$

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

$\theta_1 = 35^{\circ}$ is the angle of incidence of the wave in water

$\theta_2$ is the angle of refraction of the wave in air

Solving for the angle of refraction,

$sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}$

fiasKO [112]3 years ago

3 0

Answer:

49.7

Explanation:

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Tcecarenko [31]

Answer:

Resistor

Explanation:

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3 years ago

What would always be true of an object possessing a potential energy of 0 joules

Elenna [48]

if the object has 0 potential energy it means it is on ground ..
explanation :
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3 years ago

Two ac generators supply the same voltage. However, the first generator has a frequency of 1.2 kHz, and the second has a frequen

astra-53 [7]

Answer:

I_2 = 0.146 A

Explanation:

The formula for current in an inductor is;

I_rms = V_rms/X_L

Where X_L is inductance wirh formula 2πfL

So, I_rms = V_rms/X_L

Applying this to the two generators, we have;

First generator;

I_1 = V_rms/(2π(f_1)L)

And I_2 = V_rms/(2π(f_2)L)

Thus, to find the current in the second generator, we divide eq 1 by eq 2;

So,

I_2/I_1 = [V_rms/(2π(f_2)L)]/[V_rms/(2π(f_1)L)]

Some values will cance out leaving us with;

I_2/I_1 = f_1/f_2

I_2 = I_1(f_1/f_2)

Plugging in the relevant values ;

I_2 = 0.56(1.2/4.6)

I_2 = 0.146 A

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4 years ago

At depths of greater than 60 m, ice moves by plastic deformation. What causes this transition from brittle to ductile behavior?

mafiozo [28]

Answer:

Increase in the intensity of pressure allows very less deformation

Explanation:

For the water the variation of pressure at any depth is directly proportional to the depth of the water above that level.

Thus, at depth greater than 60 m the intensity of pressure on ice is very high and therefore very little deformation is possible.

Hence, the transition from brittle to ductile behavior is observed.

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4 years ago

When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees

nexus9112 [7]

(a) The man comes to a halt in 1.99 ms = 1.99 × 10⁻³ s, so his average acceleration slowing him from 6.33 m/s to a rest is

a = (6.33 m/s - 0) / (1.99 × 10⁻³ s) ≈ 3180 m/s²

so that the average net force on the man during the landing is

F = (70.8 kg) a ≈ 225,000 N

i.e. with magnitude 225,000 N.

(b) With knees bent, the man has an average acceleration of

a = (6.33 m/s - 0) / (0.147 s) ≈ 43.1 m/s²

and hence an average net force of

F = (70.8 kg) a ≈ 3050 N

(c) The net force on the man is

∑ F = n - w = m a

where

n = magnitude of the normal force, i.e. the force of the ground pushing up on the man

w = the man's weight, m g ≈ 694 N

m = the man's mass, 70.8 kg

g = mag. of the acceleration due to gravity, 9.80 m/s²

a = the man's acceleration

Using the acceleration in part (b), we have

n = m g + m a = m (g + a)

n = (70.8 kg) (9.80 m/s² + 43.1 m/s²) ≈ 3740 N

4 0

3 years ago