Answer:
Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.
Explanation:
Answer:
Yes
Explanation:
In a third-class lever, the effort force lies between the resistance force and the fulcrum. Some kinds of garden tools are examples of third-class levers. When you use a shovel, for example, you hold one end steady to act as the fulcrum, and you use your other hand to pull up on a load of dirt.
Answer:
the study of geological factors and the ways the earth
Answer:
691.13 nm
Explanation:
d = width of the slit = 0.11 x 10⁻³ m
θ = angle of diffraction pattern = 0.72° degree
λ = wavelength of the light = ?
m = order = 2 (since second minimum)
for the second minimum diffraction pattern we use the equation
d Sinθ = m λ
Inserting the values
(0.11 x 10⁻³) Sin0.72 = (2) λ
λ = 691.13 x 10⁻⁹ m
λ = 691.13 nm
Answer: B) 0.00337 m3.
Explanation:
Given data:
Mass of the ball = 10kg
Weight of the ball in air = 98N
Weight of the ball in water = 65N
Solution:
To get the Volume of the ball when submerged in water, we divide the weight of the ball in water with the difference in apparent weight by 9.8m/s^2.
= 98 - 65 / 9.8
= 33 / 9.8
= 3.37kg
The volume of the ball is 3.37kg
The density of water is 1kg per Liter.
So 3.37 kg of water would have a volume of 3.37 Liters.
Therefore the ball would have a volume of 3.37 Liters (or 0.00337 cubic meters).
