The maximum height attained is 460 m.
<h3>What is the maximum height?</h3>
We know that the final velocity of a body is 0 m/s at the maximum height which is the greatest height that is attained by the body. We now use the formula;
v^2 = u^2 -2gh
Given that v = 0 m/s
u^2 = 2gh
h = u^2/2g
v = final velocity
u = initial velocity
h = maximin height
g = acceleration due to gravity
h = (95)^2/2 * 9.8
h = 460 m
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The genotype for all offspring will be Pp making the flower color white.
Answer:
B) the change in momentum
Explanation:
Impulse is defined as the product between the force exerted on an object (F) and the contact time (
)
Using Newton's second law (F = ma), we can rewrite the force as product of mass (m) and acceleration (a):
However, the acceleration is the ratio between the change in velocity (
) and the contact time (): 
, so the previous equation becomes
And by simplifying ,
which corresponds to the change in momentum of the object.
Answer: 91.4 J
Explanation:
Kinetic energy is the energy possessed by a body due to virtue of its motion.
K.E. = 0.5 m v²
Mass of the continent is given, m = 1.819 × 10²¹ kg
Side of the block of continent, s = 4150 km = 4150000 m
Depth of the block of continent, d = 38 km = 38000 m
(Mass = density × volume
m = 2780 kg/m³× (4150 × 10³ m)²× 38 × 10³ m = 1.819 × 10²¹ kg)
The continent is moving at the rate of, v = 1 cm /year = 0.01 m / 31556926 s = 3.17 × 10⁻¹⁰ m/s
⇒ K.E. = 0.5 × 1.819 × 10²¹ kg × (3.17 × 10⁻¹⁰ m/s)²= 91.4 J
Hence, mass of the continent has 91.4 J of kinetic energy.
Answer:
E/4
Explanation:
The formula for electric field of a very large (essentially infinitely large) plane of charge is given by:
E = σ/(2ε₀)
Where;
E is the electric field
σ is the surface charge density
ε₀ is the electric constant.
Formula to calculate σ is;
σ = Q/A
Where;
Q is the total charge of the sheet
A is the sheet's area.
We are told the elastic sheet is a square with a side length as d, thus ;
A = d²
So;
σ = Q/d²
Putting Q/d² for σ in the electric field equation to obtain;
E = Q/(2ε₀d²)
Now, we can see that E is inversely proportional to the square of d i.e.
E ∝ 1/d²
The electric field at P has some magnitude E. We now double the side length of the sheet to 2L while keeping the same amount of charge Q distributed over the sheet.
From the relationship of E with d, the magnitude of electric field at P will now have a quarter of its original magnitude which is;
E_new = E/4
