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podryga [215]
2 years ago
15

It takes a car one minute to go from rest to 30m/s east. Whqt is the acceleration of this car?

Physics
1 answer:
zavuch27 [327]2 years ago
5 0

Answer:

0.5 m/s^{2}

Explanation:

a = \frac{v-u}{t} \\a = \frac{30 m/s}{60 s} \\a = 0.5 m/s^2

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Creates an image that appears upside down behind the focal point
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An image that appears upside down behind the focal point is an image that is reflected on a concave mirror. Mirrors reflect different kinds of images based on the placement of an object that is reflected towards it. There are two kinds of mirrors, concave and a convex mirrors, the latter makes objects seem smaller and farther than where it is exactly.
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Melissa's favorite exercise equipment at the gym consists of various springs. in one exercise, she pulls a handle grip attached
konstantin123 [22]

The formula for force exerted on/by a spring is 

F = k*e where k is the spring constant and x is the distance stretched from unstrained position. This should allow you to find what you need.

 

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The F is her weight = 45 X 0.80 


= 36 N

6 0
3 years ago
How do you convert Kg's to Newtons?
MA_775_DIABLO [31]
You don't convert kilograms to newtons.  By the time you've heard of these units, you know that 'kilogram' is a unit of mass, 'newton' is a unit of force or weight, and that mass and weight are different things.

Mass and force are <u>related</u> by Newton's second law: 

                       Force = Mass x acceleration .

From this simple formula, you can see that in order to relate a mass to a force, you need to know an acceleration.  And if the acceleration changes, then the relationship between the force and the mass also changes.  So there's no direct conversion.

ON EARTH ONLY, one kilogram of mass <em>weighs</em> 9.8 newtons. The acceleration that connects them is the acceleration of gravity on Earth.  In other places, with different gravitational accelerations, 1 kilogram weighs more or less newtons.

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3 years ago
One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit
nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

\lambda = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

\theta=\dfrac{1.22\lambda}{D}

The width is given by

d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m

The required width is 0.000003782 m

Minimum resolvable line separation is given by

\dfrac{0.000003782}{2}=0.000001891\ m

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when \lambda=157\ nm

d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m

The new minimum resolvable line separation between adjacent lines is

\dfrac{0.00000239425}{2}=0.000001197125\ m

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3 years ago
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