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34kurt
3 years ago
8

Light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li

ght travels in one year.
Calculate the distance of one light year in feet.
Physics
1 answer:
Anastasy [175]3 years ago
8 0

Answer: 3.142656 × 10^16 feet

Explanation: Given that the

Speed = 982,080,000 ft/s, and

Time = 32,000,000 seconds

The formula for speed is:

Speed = distance/ time

Make distance the subject of formula

Since the time is second in one year and speed is ft/s, substitute both into the formula

Distance = speed × time

distance = 982,080,000 × 32,000,000

Distance = 3.142656 × 10^16 feet.

The distance of one light year in feet is 3.142656 × 10^16

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alexandr402 [8]

Answer:

Sound waves transfer energy by causing successive compressions and rarefactions in the particles of the medium without transporting the medium particles themselves. Sound in solids can also manifest as transverse waves, causing crests and troughs in the propagation medium.

6 0
2 years ago
URGENT!!!
madreJ [45]

Answer:

f=6.97\times 10^{14}\ Hz

Explanation:

Given that,

Wavelength, \lambda=430\ nm=430\times 10^{-9}\ m

We need to find the frequency of the violet light.

We know that the relation between frequency and wavelength is given by :

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{430\times 10^{-9}}\\\\f=6.97\times 10^{14}\ Hz

So, the frequency of violet light is 6.97\times 10^{14}\ Hz.

7 0
3 years ago
A friend tells you that a lunar eclipse will take place the following week, and invites you to join him to observe the eclipse t
WARRIOR [948]

Answer:

y = 80.2 mille

Explanation:

The minimum size of an object that can be seen is determined by the diffraction phenomenon, if we use the Rayleigh criterion that establishes that two objects can be distinguished without the maximum diffraction of a body coincides with the minimum of the other body, therefore so much for the pupil of the eye that it is a circular opening

          θ = 1.22 λ/ d

in a normal eye the diameter of the pupils of d = 2 mm = 0.002 m, suppose the wavelength of maximum sensitivity of the eye λ = 550 nm = 550 10⁻⁹ m

         θ = 1.22 550 10⁻⁹ / 0.002

         θ = 3.355 10⁻⁴ rad

Let's use trigonometry to find the distance supported by this angle, the distance from the moon to the Earth is L = 238900 mille = 2.38900 10⁵ mi

       tan θ = y / L

       y = L tan θ

       y = 2,389 10⁵ tan 3,355 10⁻⁴

       y = 8.02 10¹ mi

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This is the smallest size of an object seen directly by the eye

5 0
3 years ago
Which of these are a covalent compound?
nikdorinn [45]
C is a non-metal and so is O. So the answer is CO
8 0
2 years ago
In a particular case of an object in front of a spherical mirror with a focal length of +12.0 cm, the magnification is +4.00.(a)
salantis [7]

Answer:

9 cm

-36 cm

Explanation:

u = Object distance

v = Image distance

f = Focal length = 12

m = Magnification = 4

m=-\frac{v}{u}\\\Rightarrow 4=-\frac{v}{u}\\\Rightarrow v=-4u

Lens equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{12}=\frac{1}{u}+\frac{1}{-4u}\\\Rightarrow \frac{1}{12}=\frac{3}{4u}\\\Rightarrow u=9\ cm

Object distance is 9 cm

v=-4\times 9=-36\ cm

Image distance is -36 cm (other side of object)

7 0
3 years ago
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