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Svetlanka [38]
3 years ago
10

In parallelogram ABCD point K belongs to diagonal

Mathematics
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer:

\dfrac{BE}{EC}=\dfrac{1}{3}.

Step-by-step explanation:

Consider triangles BKE and DKA. In this triangles:

  • \angle BKE=\angle DKA as vertical angles;
  • \angle KBE=\angle KDA as alternate interior angles (lines BC and AD are parallel and BC is a transversal);
  • \angle BEK=\angle DAK as alternate interior angles (lines BC and AD are parallel and BE is a transversal).

Thus triangles BKE and DKA are similar by AA theorem. Similar triangles have proportional sides lengths:

\dfrac{BK}{KD}=\dfrac{BE}{AD}\Rightarrow \dfrac{1}{4}=\dfrac{BE}{AD}.

Thus, AD=4BE.

Since AD=BC and BC=BE+CE, we have that 4BE=BE+EC, EC=3BE. Hence, the ratio BE to EC is

\dfrac{BE}{EC}=\dfrac{BE}{3BE}=\dfrac{1}{3}.

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Answer:

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Step-by-step explanation:

We start by writing the equation that links x and y

From the question;

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When we talk of range, we are referring to the values on the y-axis

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Answer

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Step-by-step explanation

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~ Hoodini, here to help :)
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Step-by-step explanation:

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Step-by-step explanation:

I hope this is helpful to you

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