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Fofino [41]
3 years ago
13

1. In how many ways can a committee of eight people to be formed from a group of 6 male, 5 female and 4 students if there are no

restrictions, as all members are eligible?
Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

The number of ways is 6435

Step-by-step explanation:

Given

Male = 6

Female = 5

Students = 4

Required

Number of ways a group of 8 can be formed

Here, I'll assume each category of people are distinct:

Hence;

Total = Male + Female + Students

Total = 6 + 5 + 4

Total = 15

Number of ways is then calculated as follows:

^nC_r = \frac{n!}{(n - r)!r!}

Where

n = 15\ and\ r = 8

So, we have:

^{15}C_8 = \frac{15!}{(15 - 8)!8!}

^{15}C_8 = \frac{15!}{7! * 8!}

^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9 * 8!}{7!8!}

^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9}{7!}

^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9}{7 * 6 *5 * 4 * 3 * 2 * 1}

^{15}C_8 = \frac{32432400}{5040}

^{15}C_8 = 6435

<em>Hence, the number of ways is 6435</em>

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Answer:

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Step-by-step explanation:

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We know there’s 660 boxes and each box called for 3 eggs, therefore:

660=3X

when divide both sides by 3 to isolate the x, which will tell us the amount of eggs used…

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2 years ago
What is the nth term of 5,11,17,23
rewona [7]

Answer:

6n - 1.

Step-by-step explanation:

Arithmetic sequence.

a1 = 5, d = 6.

nth term = a1 + d(n - 1)

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3 years ago
Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar
bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\

A. P(x=6)

P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\

B. P(x≥10)

P(x\geq10)=1-P(x

P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\

P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\

P(x\geq10)=1-(0.0008+0.0063+0.0251+0.0641+0.1175+0.1645+0.1828+0.1654+0.1241+0.0781)\\\\P(x\geq10)=1-0.9287=0.0713

C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

E(x)=\mu=n\cdot p=25\cdot 0.25=6.25\\\\\sigma=\sqrt{np(1-p)}=\sqrt{25\cdot 0.25\cdot 0.75}=\sqrt{4.69}\approx2.17

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Answer:

1 5/9

Step-by-step explanation:

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