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Fofino [41]
3 years ago
13

1. In how many ways can a committee of eight people to be formed from a group of 6 male, 5 female and 4 students if there are no

restrictions, as all members are eligible?
Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

The number of ways is 6435

Step-by-step explanation:

Given

Male = 6

Female = 5

Students = 4

Required

Number of ways a group of 8 can be formed

Here, I'll assume each category of people are distinct:

Hence;

Total = Male + Female + Students

Total = 6 + 5 + 4

Total = 15

Number of ways is then calculated as follows:

^nC_r = \frac{n!}{(n - r)!r!}

Where

n = 15\ and\ r = 8

So, we have:

^{15}C_8 = \frac{15!}{(15 - 8)!8!}

^{15}C_8 = \frac{15!}{7! * 8!}

^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9 * 8!}{7!8!}

^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9}{7!}

^{15}C_8 = \frac{15 * 14 * 13 * 12 * 11 * 10 * 9}{7 * 6 *5 * 4 * 3 * 2 * 1}

^{15}C_8 = \frac{32432400}{5040}

^{15}C_8 = 6435

<em>Hence, the number of ways is 6435</em>

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Answer:

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