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4 years ago

Explain how a set of numbers can have a greatest common factor greater than one

Mathematics

2 answers:

Elis [28]4 years ago

7 0

6b 240
6c 216
6d 480
6e 72
6f 280

KATRIN_1 [288]4 years ago

7 0

Say you need to find a common factor for 3 and 7 just multiply 3 times 7 to get 21, and 7 times 3 to get 21. 21 is the greatest common factor.

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Tara wants to order tickets online so that she and three of her friends can go to the movies together. The cost of the tickets i

vichka [17]

Answer:

16×4= 64

64.00+3.50

(16×4)+(64.00+14.00)

Step-by-step explanation:

First you have to find how much the tickets will cost per person then add 14.00 because of the one time person but there is four so time 3.50×4

5 0

3 years ago

Solve for all values of x by factoring. x^2-5x=-2x

-Dominant- [34]

Answer:

x = 0

x = 3

Step-by-step explanation:

$x^2 - 5x = -2x\\x^2 - 5x + 2x = 0\\x^2 - 3x = 0\\x(x - 3) = 0\\x=0 , x-3=0\\x=0, x=3$

4 0

3 years ago

1+4 = 5 2+5 = 12 3+6 = 19 8+11 = ?

s344n2d4d5 [400]

1+4=5

2+5=7

5+7=12

3+6=9

12+9=21

I do not see21 up here so please cheek your question again or please change the 19 to a 21

3 0

3 years ago

Ms. Simonetti mows the lawn with a gas lawn mower. In order to work, oil

Monica [59]

Report this clown who put the first answer he’s trying to get your ip

3 0

3 years ago

Please help answer the question.

muminat

Answer:

a. $\dfrac{y^8}{x^{10}}$

Step-by-step explanation:

First step is ti distribute the exponent outside the parenthesis. According to the law of exponents, you need to distribute it to each variable.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}\\\\=\dfrac{x^{(-4\times-2)}y^{(1\times-2)}}{x^{(-9\times-2)}y^{(5\times-2)}}\\\\=\dfrac{x^{8}y^{-2}}{x^{18}y^{-10}}$

Now again, following the law of exponents, if you have negative exponents, you put them in the opposite side of the fraction.

$=\dfrac{x^8y^{-2}}{x^{18}y^{-10}}\\\\=\dfrac{x^8y^{10}}{x^{18}y^{2}}\\\\$

Next, when it comes to division, we subtract the exponents of the numerator and the denominator of similar variables.

$=\dfrac{x^8y^{10}}{x^{18}y^{2}}\\\\=x^{(8-18)}y^{(10-2)}\\\\=x^{-10}y^8$

Since the exponent of x is negative, we move it below the fraction.

$\dfrac{y^8}{x^{10}}$

6 0

3 years ago