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Mkey [24]
3 years ago
6

A student measures a mass of an 8cm3 block of brown sugar to be 19.9G. what is the density of the brown sugar?

Chemistry
1 answer:
Naily [24]3 years ago
3 0

Answer:

<h2>2.49 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{19.9}{8}  \\  = 2.4875

We have the final answer as

<h3>2.49 g/cm³</h3>

Hope this helps you

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Question 1<br>Which of the following is a false​
Bogdan [553]

Answer:

1.A 2.C 3.B

4. d

Explanation:

6 0
3 years ago
A student used a vernier magnetic field sensor to measure the strength of the magnetic field generated by a bar magnet. at which
yaroslaw [1]

The position is the strength of the magnetic field strongest is is the place where the magnetic field leaves, being point A.

<h3>What generates a magnetic field?</h3>

When an electrically charged particle moves, it creates a magnetic field. According to the laws of electromagnetism, this magnetic field originates from the variation of the electric field strength.

In the region of the poles we see that the lines of magnetic induction are closer to each other, therefore, we consider that close to the poles the magnetic field is more intense.

See more about magentic field at brainly.com/question/14848188

#SPJ1

5 0
2 years ago
4.41 g of propane gas (C3H8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below
gayaneshka [121]

Answer :  The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

q_{rxn}=-q_{cal}

q_{cal}=c_{cal}\times \Delta T

where,

q_{rxn} = heat released by the reaction = ?

q_{cal} = heat absorbed by the calorimeter

c_{cal} = specific heat of calorimeter = 97.1kJ/^oC=97100J/^oC

\Delta T = change in temperature = (T_{final}-T_{initial})=(27.282-25.000)=2.282^oC

Now put all the given values in the above formula, we get:

q_{cal}=(97100J/^oC)\times (2.282^oC)

q_{cal}=221582.2J=221.6kJ

As, q_{rxn}=-q_{cal}

So, q_{rxn}=-221.6kJ

Thus, the heat of the reaction is -221.6 kJ

6 0
3 years ago
1. Imagine you have a sealed 20.0 L balloon filled with helium gas at 750 mmHg in the
SVETLANKA909090 [29]

Answer:

17.6510 L

Explanation:

First we should get the number of moles of helium here by Boyle's law

PV=nRT

P=750/760= 0.9868 atm

T=25+273=298 kelvin

R= 0.08206

V= 20L

so

n=PV/RT

n=0.9868×20/0.08206×298

n=0.80707 mol

Then use the same law

V=0.80707×0.08206×263/0.9869=

17.6510L

SO THE VOLUME WILL BE 17.6510 L

6 0
2 years ago
Please help due today
nasty-shy [4]
I think it’s A not sure though
7 0
3 years ago
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