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Contact [7]
3 years ago
7

In atoms, electrons surround the nucleus in?

Chemistry
2 answers:
kolbaska11 [484]3 years ago
6 0

The answer is B specific energy levels

Charra [1.4K]3 years ago
4 0

either the answer is  B or D

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What does how will u experiment mean in making a science project
Lady_Fox [76]
How are you going to experiment means how will you show your project in a real life situation like a penny being cleaned with different acids.
7 0
4 years ago
2NaOH + H2SO4 ------> 2 H2O + Na2SO4
balandron [24]

\huge\fbox{Answer ☘}

It is given in the question that 200.0 grams of sodium hydroxide reacts with excess of sulphuric acid.

The given reaction is shown below

\bold\blue{2NAOH + H _{2}SO _{4}  \: - > 2H _{2} O+ NA _{2}SO_{4} }\\

In this reaction, two mole of sodium hydroxide react with one mole of sulphuric acid to give two mole of water and one mole of sodium sulfate.

To determine the mass of sodium sulfate, first calculate the moles of sodium hydroxide as the value of mass is provided.

The molecular weight of NaOH is 40 g/mol.

The formula is shown below.

\pink{n =  \frac{m}{ M}}\\

Where,

✫ n is the number of moles

✫ m is the mass

✫ M is the molecular weight

To calculate the number of moles, substitute the values in the above equation.

\pink{n =  \frac{200.0}{40g \: mol {}^{ - 1} } } \\  \\\pink{ ⇢n = 5}

In the equation it is given that 2 mole of sodium hydroxide gives 1 mole of sodium sulphate.

So, to determine the actual mole of sodium sulfate divide the calculated moles of NaOH by 2.

\pink{⇢  \frac{5}{2}}  \\   \\  \pink{⇢ 2.5 \: mol}

So 2.5 mol sodium sulfate is formed from 5 mol NaOH.

The molecular weight of sodium sulfate is 142.1 g/mol.

To calculate the mass of sodium sulfate, substitute the values in the formula.

\pink{⇢2.5 =  \frac{m}{142.1g \: mol {}^{ - 1} } } \\  \\\pink{ ⇢ m = 2.5 \times 142.1 }\\  \\ \pink{⇢ m = 355.25}

Therefore, the mass of sodium sulfate formed when we start with 200.0 grams of sodium hydroxide and you have excess sulphuric acid is 355.25g.

hope helpful~

5 0
2 years ago
Balance the double replacement: <br> Mn(SO4)2 + K2S2O3 =
Firlakuza [10]

Answer:

        Mn(SO₄)₂ + 2 K₂S₂O₃ ----------> Mn(S₂O₃)₂ + 2 K₂SO₄

Explanation:

Reaction Given:

              Mn(SO₄)₂ + K₂S₂O₃ =

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

For example if the Sulfur at the reactant side is 6, the number of Sulfurmust be 6 on the product side.

First we Complete the reaction

                  Mn(SO₄)₂ + K₂S₂O₃ ----------> Mn(S₂O₃)₂ + K₂SO₄

Check the chemical equation and count the number of atoms at the reactant side and product side.

If the number of atoms of the reactants equal to the number of atoms of products then the reaction is balanced but if not equal, then reaction is not balanced

Balancing is an trial and error process to get a balance reaction.

First we count the number of atoms of reactant and product

             Mn(SO₄)₂ + K₂S₂O₃ ----------> Mn(S₂O₃)₂ + K₂SO₄

Number of atoms of Reactant:

Mn = 1

S = 4

O = 7

K = 2

Number of atoms of Product:

Mn = 1

S = 5

O = 10

K = 2

So this is not a balance equation as the atoms of the reactant atoms not equal to the number of the product atoms.

As there are 4 Sulfur, and 7 oxygen atoms at reactant side but 5 Sulfur, and 10 oxygen atoms at the product side so we balance this along with other

Balanced Equation:

          Mn(SO₄)₂ + 2 K₂S₂O₃ ----------> Mn(S₂O₃)₂ + 2 K₂SO₄

Now count the number of atoms of reactant and product

Number of atoms of Reactant:

Mn = 1

S = 6

O = 14

K = 4

Number of atoms of Product:

Mn = 1

S = 5

O = 10

K = 2

Now this reaction is balanced as the atoms of the reactant atoms equal to the number of the product atoms.

So,

the Coefficient of  K₂S₂O₃ and K₂SO₄ is 2 in balanced equation

4 0
3 years ago
Which natural polymers are involved with making clothing?
fredd [130]

Answer:

A. wool, silkworm, cocoon, and cellulose

Explanation:

I hope this helped!

7 0
3 years ago
Read 2 more answers
Which metals may be oxidized by H+ under standard-state conditions? Ag+(aq) + e– → Ag(s) E° = 0.80 V Cu2+(aq) + 2e– → Cu(s) E° =
Debora [2.8K]
Answer is: tin and zinc, because they standard potential as less than zero.
Tin and zinc are oxidized to tin and zinc cations (with +2 charge) and hydrogen anions are reduced to hydrogen molecules with neutral charge.
Zn → Zn²⁺ + 2e⁻; 2H⁺ + 2e⁻ → H₂.
<span>Oxidation is increase of oxidation number  and reduction is decrease of oxidation number.</span>
8 0
3 years ago
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