Answer:
8L of CO2
Explanation:
The equation for the reaction is given below:
2C2H2 + 5O2 —> 4CO2 + 2H2O
From the equation above,
5L of O2 produced 4L of CO2.
Therefore, 10L of O2 will produce = (10 x 4)/5 = 8L of CO2
Therefore, 8L of CO2 is produce
Limitations of Van der waal's equation. (i) The value of 'b' is not constant but varies with pressure and temperature. (ii) The value of is not equal to 3b, but actually it is equal to, in some case; and in other cases 2b. (iii) The value of is not equal to but it is usually more than 3 for most of the gases.
Because they can't get trapped in.
If its a acid it will be 3 or if its a alkali then 14 or neutral then 7
0.2M means 0.2mol CaCl2/1L solution.
This question didn't give us a density of the solution so needs an assumption that the solution has equal volume to water.
xmol/0.5L=0.2M
x = 0.1
0.1mol of CaCl2 is needed. Ca=40g/mol, Cl=35.5g/mol.
CaCl2 0.1mol = (40+35.5*2)*0.1=11.1g
