A beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 40° with the normal
1 answer:
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Answer:
1.35m
Explanation:
At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.
The vertical speed at the jumping point can be computed:
When the skier jumps to the its potential energy is converted to kinetic energy:
where m is the skier mass and h is the vertical distance traveled, is the vertical velocity at jumping point, and h is the highest point.
Let g = 10m/s2
We can divide both sides of the equation by m:
Answer:
a)1.93 kg-m^2
b) 1.45 kg-m^2
c) = 0
d) 1.15 kg-m^2
Explanation:
mass of the bar M = 4 kg
length of the bar = 2 m
mass of balls m1= m2= 0.3 kg
moment of inertia of bar
about an axis perpendicular to the bar through its center.
a) MOI of bar + 2×m×(L/2)^2
+
now putting the values of m, M and L as above and solving we get
I= 1.93 kg-m^2
b) perpendicular to the bar through one of the balls
= 1.45 kg-m^2
c) parallel to the bar through both balls
zero as the no mass distribution along the parallel to the bar through both balls.
d) parallel to the bar and 0.500 m from it.
I=
putting values and solving we get
1.15 kg-m^2