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Fofino [41]
4 years ago
10

Please help!!!!

Physics
1 answer:
Nata [24]4 years ago
7 0

Answer:3*10^14v/m

Explanation:

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Uniform solid disk rolls without slipping down a 19.0° inclined plane. what is the acceleration of the disk's center of mass?
coldgirl [10]
Below is the solution:

Let us say that the disk goes through a vertical elevation change of one meter. 

<span>The change in potential energy will equal the change in kinetic energy </span>

<span>PE = KEt + KEr </span>
<span>mgh = ½mv² + ½Iω² </span>

<span>for a uniform disk, the moment of inertia is </span>
<span>I = ½mr² </span>
<span>and </span>
<span>ω = v/r </span>

<span>mgh = ½mv² + ½(½mr²)(v/r)² </span>
<span>mgh = ½mv² + ¼mv² </span>
<span>gh = ¾v² </span>

<span>v² = 4gh/3 </span>

<span>v² = u² + 2as </span>

<span>if we assume initial velocity is zero </span>

<span>v² = 2as </span>
<span>a = v² / 2s </span>

<span>s(sinθ) = h </span>
<span>s = h/sinθ </span>

<span>a = 4gh/3 / 2(h/sinθ) </span>
<span>a = ⅔gsinθ </span>

<span>a = ⅔(9.8)sin25 </span>
<span>a = 2.8 m/s² </span>
3 0
4 years ago
An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper
bixtya [17]

Answer:

a. P=18.61\ W

b. \eta_c=0.6976=69.76\%

c. \eta=0.4718=47.18\%

Explanation:

Given:

  • temperature of the hotter reservoir, T_H=1250\ K
  • temperature of the colder reservoir, T_C=378\ K
  • heat absorbed by the engine, Q_H=1.42\times 10^{5}\ J
  • heat rejected to the cold reservoir, Q_L=7.5\times 10^4\ J
  • time duration of the energy transfer, t=1\ hr=3600\ s

<u>Now the work done by the engine:</u>

Using energy conservation,

W=Q_H-Q_L

W=14.2\times 10^4-7.5\times 10^4

W=6.7\times 10^4\ J

a.

<u>Hence the power output:</u>

P=\frac{W}{t}

P=\frac{6.7\times 10^4}{3600}

P=18.61\ W

b.

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{378}{1250}

\eta_c=0.6976=69.76\%

c.

now actual efficiency:

\eta=\frac{W}{Q_H}

\eta=\frac{6.7\times 10^4}{1.42\times 10^{5}}

\eta=0.4718=47.18\%

6 0
4 years ago
Help ASAP PLEASE.............:3​
Evgesh-ka [11]

Answer:

temperature measures heat - the unit is Celsius - and it is measured with a thermometer.

length is measuring how long, tall, or wide something is  - the base unit it metres - and it is measured with a ruler or a metre stick

volume is measuring the quantity of a three dimensional space - the unit is cubic centimetre - you find volume by taking the measurements with a ruler

mass is measuring how much space something takes up/ weight - unit is the gram - you use a scale

8 0
3 years ago
The radius of the base of a wooden cylinder 2m and its altitude is 7m. What is its mass?​
Leviafan [203]

Answer:

88 m ^2

Explanation:

8 0
3 years ago
Two adjacent natural frequencies of an organ pipe are AMT determined to be 550 Hz and 650 Hz. Calculate (a) the M fundamental fr
allochka39001 [22]

Answer:

The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

Explanation:

Given that,

Frequency f = 550 Hz

Frequency f' = 650 Hz

We know that,

AMT pipe is open pipe.

(b). We need to calculate the length of the pipe

Using formula of organ pipe

f=\dfrac{nv}{2L}

For 550 Hz,

550=\dfrac{n\times340}{2L}...(I)

For 650 Hz,

650=\dfrac{(n+1)\times340}{2L}...(II)

From equation (I) and (II)

550-650=\dfrac{340}{2L}-\dfrac{340}{L}

L=\dfrac{340}{2\times100}

L=1.7\ m

(a). We need to calculate the fundamental frequency for n = 1

Using formula of  fundamental frequency

=f=\dfrac{n\lambda}{2L}

put the value of L

f=\dfrac{1\times340}{2\times1.7}

f=100\ Hz

Hence, The fundamental frequency and length of the pipe are 100 Hz and 1.7 m.

4 0
3 years ago
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