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jeka94
3 years ago
11

How are speed and velocity alike?

Physics
2 answers:
Levart [38]3 years ago
7 0

Answer:

im pretty sure B

Explanation:

vlabodo [156]3 years ago
3 0

Answer:

B

Explanation:

They both describe a rate of motion

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How many basic locomotor skills are there?
CaHeK987 [17]
Eight and I don’t know what else to say but for sure 8
4 0
3 years ago
A sled starts from rest,
Marrrta [24]

Answer:

25.6 m/s

Explanation:

Draw a free body diagram of the sled.  There are two forces acting on the sled:

Normal force pushing perpendicular to the hill

Weight force pulling straight down

Take sum of the forces parallel to the hill:

∑F = ma

mg sin θ = ma

a = g sin θ

a = (9.8 m/s²) (sin 38.0°)

a = 6.03 m/s²

Given:

v₀ = 0 m/s

a = 6.03 m/s²

t = 4.24 s

Find: v

v = at + v₀

v = (6.03 m/s²) (4.24 s) + (0 m/s)

v = 25.6 m/s

5 0
3 years ago
2. Two charges at fixed locations produce an electric field as shown
vagabundo [1.1K]

Answer:

sum of the two forces as both point to the right is a force that points to the right,

Explanation:

The force on the cast load at point Y is given by

        F = q_y  E

force is a vector magnitude so its result is

        ∑ F = Fₐ + F_b

indicate that the charge at y is negative, we analyze the direction of the force created by each charge

Charge A

as the electric field is incoming the charge is negative and as the test charge is negative both repel each other, consequently the force points to the right

Charge B

in this case the electric field lines are salient, therefore the charge is positive, consequently the force on the charge at y is attractive and points to the right

the sum of the two forces as both point to the right is a force that points to the right, that is, in the direction of the charge located at B

3 0
3 years ago
How does the wind turbine generator work?
AnnZ [28]

Answer: wind pushes directly against the blades of the turbine, which converts the linear motion of the wind into the rotary motion, then it spins the generator's rotor and the harder the wind pushes, the more electrical energy can be generated.

Explanation:

5 0
3 years ago
The orbital period of a satellite is 2 × 106 s and its total radius is 2.5 × 1012 m. The tangential speed of the satellite, writ
LenaWriter [7]

The orbital period of the satellite[T] is given as 2*10^{6} S.

The radius of the satellite is given [R] 2.5*10^{12} m.

we are asked here to calculate the tangential speed of the satellite.

Before going to get the solution first we have understand the tangential speed.

The tangential speed of a satellite is given as the speed required to keep the satellite along the orbit. If satellite speed is less than tangential speed,there is the chance of it falling down towards earth. If it is more,then it will deviate from it orbit and can't stick to the orbit further.In a simple way  the tangential speed is the linear speed of an object in a circular path.

Now we have to calculate the tangential speed [V].

Mathematically the tangential speed [V]   written as -

                                V=\frac{2\pi R}{T}

where T is the time period of the satellite and R is the radius of the satellite.

                        V=\frac{2*3.14*10^{12} }{2*10^{6} }

                               = 7.85*10^{6} m/s

There is also another way through which we can get  the solution as explained below-

We know that the tangential speed of a satellite V=\sqrt{\frac{GM}{R^{2} } }

where G is the gravitational constant and M is the mas of central object.

But we know that g=\frac{GM}{R^{2} }

                               ⇒GM=gR^{2}  where g is the acceleration due to gravity of that central object.


Hence    V=\sqrt{\frac{gR^{2} }{R} }

               ⇒   V=\sqrt{gR}

By knowing the value of g due to that central object we can also calculate its tangential speed.

                           

 




7 0
3 years ago
Read 2 more answers
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