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seropon [69]
3 years ago
13

An ambulance driver traveling at 31.0 m/s (69.3 mph) honks his horn as he sees a motorist ahead on the highway traveling in the

same direction. The motorist hears a frequency of 392 Hz and notices that his own speedometer reads 44.7 mph (20.0 m/s). Calculate the frequency that the ambulance driver hears. (Speed of sound is 340 m/s) (in Hz)
Physics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

fo = 378.52Hz

Explanation:

Using Doppler effect formula:

f'=\frac{C-Vb}{C-Va}*fo

where

f' = 392 Hz

C = 340m/s

Vb = 20m/s

Va = 31m/s

Replacing these values and solving for fo:

fo = 378.52Hz

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A wire of Nichrome (a nickel– chromium– iron alloy commonly used in heating elements) is 1.0 m long and 1.0 mm² in cross-se
Lyrx [107]

Answer:

The conductivity of Nichrome is 2\times 10^6\ S/m.

Explanation:

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:

R=\frac{V}{A}=\frac{2.0}{4.0}=0.5\ \Omega

Now, resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:

R=\rho\frac{L}{A}

Where, \rho\to resistivity\ of\ Nichrome

Now, plug in all the values given and solve for \rho. This gives,

0.5\ \Omega=\rho\frac{1.0\ m}{1\times 10^{-6}\ m^2}\\\\\rho=\frac{0.5\times 1\times 10^{-6}}{1.0}=0.5\times 10^{-6}\ \Omega-m

Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

\sigma=\frac{1}{\rho}=\frac{1}{0.5\times 10^{-6}}=2\times 10^6\ S/m

Conductivity is measured in Siemens per meter (S/m)

Therefore, the conductivity of Nichrome is 2\times 10^6\ S/m.

7 0
3 years ago
HELP NOWWWWW PLEASE
Finger [1]

Answer:it is A

Explanation:

ok

7 0
3 years ago
Read 2 more answers
Which of the following statements is TRUE in regards to Signal #2?
Marina CMI [18]

Answer:

2) Signal #2 is a digital signal that transmits signals in segments/intervals.

Explanation:

Signals are form of information propagating from the source to a display unit for appropriate interpretation. It can be either in a digital or analogue form.

A digital signal is a definite signal which is discrete in time and amplitude. It is mostly in the form of codes obtained from set of values. Graphically it transmits in the form of 1 and 0, showing a point of maximum amplitude (1) and minimum amplitude (0).

Analog signal is continuous signal describing the variation of two variables with respect to time.

7 0
3 years ago
You drop a ball from a window located on an upper floor of a building. It strikes the ground with speed v. You now repeat the dr
bulgar [2K]

Answer:

 y = y₀ (1 - ½ g y₀ / v²)

Explanation:

This is a free fall problem. Let's start with the ball that is released from the window, with initial velocity vo = 0 and a height of the window i

          y = y₀ + v₀ t - ½ g t²

          y = y₀ - ½ g t²

for the ball thrown from the ground with initial velocity v₀₂ = v

         y₂ = y₀₂ + v₀₂ t - ½ g t²

     

in this case y₀ = 0

         y₂2 = v t - ½ g t²

at the point where the two balls meet, they have the same height

         y = y₂

         y₀ - ½ g t² = vt - ½ g t²

         y₀i = v t

         t = y₀ / v

since we have the time it takes to reach the point, we can substitute in either of the two equations to find the height

         y = y₀ - ½ g t²

         y = y₀ - ½ g (y₀ / v)²

         y = y₀ - ½ g y₀² / v²

        y = y₀ (1 - ½ g y₀ / v²)

with this expression we can find the meeting point of the two balls

6 0
3 years ago
A sample of O2 occupies 75 L at 1 ATM. If the volume of the sample doubles, what is the new pressure of O2?
denis23 [38]

Answer:0.50 atm

Explanation:(1atm)(75 L)=p2(150 L)

3 0
3 years ago
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