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seropon [69]
3 years ago
13

An ambulance driver traveling at 31.0 m/s (69.3 mph) honks his horn as he sees a motorist ahead on the highway traveling in the

same direction. The motorist hears a frequency of 392 Hz and notices that his own speedometer reads 44.7 mph (20.0 m/s). Calculate the frequency that the ambulance driver hears. (Speed of sound is 340 m/s) (in Hz)
Physics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

fo = 378.52Hz

Explanation:

Using Doppler effect formula:

f'=\frac{C-Vb}{C-Va}*fo

where

f' = 392 Hz

C = 340m/s

Vb = 20m/s

Va = 31m/s

Replacing these values and solving for fo:

fo = 378.52Hz

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Calculate the total resistance in a parallel circuit made up of resistances of 2, 3, and 4.
Tamiku [17]

Answer:

<em><u>0</u></em><em><u>.</u></em><em><u>9</u></em><em><u>1</u></em>

Explanation:

as equivalence resistance can be found out using the

1/Req = 1/r1 +1/r2 +1/r3......

now, 1/req= 1/2+1/3+1/4

=6/12+4/12+3/12

=13/12

i.e, req =12/13 =0.91

✌️:)

5 0
3 years ago
What would be the mass of an object that has a force of 88N and an acceleration of 12 m/s2?
MA_775_DIABLO [31]

Answer:

7.33 kg

Explanation:

F = ma

88 N = m(12 m/s^2)

m = 7.33 kg

6 0
3 years ago
Two 2.0 cm by 2.0 cm metal electrodes are spaced 1.0 mm apart and connected by wires of the terminals of a 9.0 V battery.
ale4655 [162]

Answer:

Explanation:

Area of electrodes, A = 2 cm x 2 cm = 4 cm²

Separation between electrodes, d = 1 mm

Voltage, V = 9 V

(a)

Let C is the capacitance between the electrodes

C = \frac{\epsilon _{0}A}{d}

C = \frac{8.854\times 10^{-12}\times 4\times 10^{-4}}{1\times 10^{-3}}

C = 3.54 x 10^-12 F

Let q be the charge on each of the electrode

q = C x V

q = 3.54 x 10^-12 x 9 = 3.2 x 10^-11 C

(b)

As, the battery is disconnected the charge on the electrodes remains same.

(c)

As the battery is connected the voltage is same.

capacitance is change.

As the distance is doubled, the capacitance becomes half and the charge is also halved. q' = q/2 = 1.6 x 10^-11 C

6 0
3 years ago
A ball thrown straight up takes 1.89s to reach a height of 41.6m.
yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

8 0
3 years ago
If F1 is the magnitude of the force exerted
aleksandrvk [35]

Answer: 3. F1 = F2

Explanation:

According to <u>Newton's law of Gravitation</u>, the force F exerted <u>between two bodies</u> or objects of masses M and m and separated by a distance r is equal to the product of their masses divided by the square of the distance:  

F=G\frac{Mm}{r^2} (1)

Where Gis the gravitational constant

Now, in the especific case of the Earth and the satellite, where the Earth has a mass M and satellite a mass m, being both separated a distance r, the force exerted  by the Earth on the satellite is:

F1=G\frac{Mm}{r^2}   (2)

And the force  exerted by the satellite on the Earth is:

F2=G\frac{Mm}{r^2}   (3)

As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

F1=F2

3 0
3 years ago
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