Answer:
<em><u>0</u></em><em><u>.</u></em><em><u>9</u></em><em><u>1</u></em>
Explanation:
as equivalence resistance can be found out using the
1/Req = 1/r1 +1/r2 +1/r3......
now, 1/req= 1/2+1/3+1/4
=6/12+4/12+3/12
=13/12
i.e, req =12/13 =0.91
✌️:)
Answer:
Explanation:
Area of electrodes, A = 2 cm x 2 cm = 4 cm²
Separation between electrodes, d = 1 mm
Voltage, V = 9 V
(a)
Let C is the capacitance between the electrodes


C = 3.54 x 10^-12 F
Let q be the charge on each of the electrode
q = C x V
q = 3.54 x 10^-12 x 9 = 3.2 x 10^-11 C
(b)
As, the battery is disconnected the charge on the electrodes remains same.
(c)
As the battery is connected the voltage is same.
capacitance is change.
As the distance is doubled, the capacitance becomes half and the charge is also halved. q' = q/2 = 1.6 x 10^-11 C
Answer:
Explanation:
average velocity is 41.6/1.89 = 22.0 m/s
initial velocity u is
22.0 = (u + u - 9.81(1.89))/2
44.0 = 2u - 18.5
62.56 = 2u
u = 31.3 m/s
max height is
v² = u² + 2as
s = (v² - u²) / 2a
s = (0² - 31.3²) / (2(-9.81)) = 49.9 m
49.9 = 41.6 = 8.27 m higher
In process numbers have been rounded to 3 s.d. for reporting purposes.
Answer: 3. F1 = F2
Explanation:
According to <u>Newton's law of Gravitation</u>, the force
exerted <u>between two bodies</u> or objects of masses
and
and separated by a distance
is equal to the product of their masses divided by the square of the distance:
(1)
Where
is the gravitational constant
Now, in the especific case of the Earth and the satellite, where the Earth has a mass
and satellite a mass
, being both separated a distance
, the force exerted by the Earth on the satellite is:
(2)
And the force exerted by the satellite on the Earth is:
(3)
As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:
