<h3>
Answer:</h3>
9.6724 g MgO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2Mg + O₂ → 2MgO
[Given] 5.8332 g Mg
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol Mg = 2 mol MgO
Molar Mass of Mg - 24.31 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 5 sig figs.</em>
9.67241 g MgO ≈ 9.6724 g MgO
Answer:
when an electron move closer to the nucleus the magnitude of energy of the nucleus increases
Answer:
When a sodium atom transfers an electron to a chlorine atom, forming a sodium cation (Na+) and a chloride anion (Cl-), both ions have complete valence shells, and are energetically more stable.
Answer:
Explanation:
Number of moles of CuCl2 initially present = volume * molar concentration
= 0.134 * 8
= 1.072 mol.
Molar mass of CuCl2 = 63.5 + (2*35.5)
= 134.5 g/mol
Mass of CuCl2 = molar mass * number of moles
= 134.5 * 1.072
= 144.184 g
Mass of CuCl2 in 48 ml = 5.89 g in 48 ml
Volume = 5.89 * (48/144.184)
= 1.96 ml.
The charge of the cadmium cation is +2