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NikAS [45]
3 years ago
7

Ordinary household bleach is an aqueous solution of sodium hypochlorite. what is the molarity of a bleach solution that contains

32.4 g of sodium hypochlorite in a total volume of 499 ml?
Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0
Sodium hypochlorite chemical name would be NaOCl. Then, the molecular weight should be:23 + 16 + 35.5 = <span>74.5 g/mole

Molarity unit is mole of molecule divided by 1000ml of solvent, in this case water. Then for 32.4g of molecule with 499ml solvent it would be:
32.4g / (74.5g/mole) / (1000ml/499ml)= 0.87 m</span>
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She will have symptoms of dizziness and/or lightheadedness

Explanation:

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3 years ago
Determine whether the statement about identifying a halide is true: Regardless of any concentration of ammonium solution, the pr
frosja888 [35]

Answer:

False

Explanation:

The statement ; Regardless of any concentration of ammonium solution the precipitate of unknown halide after 0.1M AgNO3 will remain is FALSE

This is Because the remaining concentration of AgNO3 is dependent on the solubility of Ag⁺

3 0
3 years ago
Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: CaO (s) + H2O (l) → Ca(OH)2 (s) In a p
dybincka [34]

Answer:

The option closest to the percentage yield is option;

d. 81.1

Explanation:

The given chemical equation of the reaction is presented as follows;

CaO (s) + H₂O (l) → Ca(OH)₂

The mass of CaO in the experiment, m = 2.00 g

The volume of water with which the CaO was reacted = Excess volume of water

Number of moles = Mass/(Molar mass)

The mass of Ca(OH)₂ recovered, actual yield = 2.14 g

The molar mass of CaO = 56.0774 g/mol

The number of moles of CaO in the reaction, n₁ = 2.00 g/(56.0774 g/mol ≈ 0.036 moles

The molar mass of Ca(OH)₂ = 74.093 g/mol

The number of moles of Ca(OH)₂ in the reaction, n₂ = 2.14 g/(74.093 g/mol) ≈ 0.029 moles

From the given chemical reaction, one mole of CaO reacts with one mole of H₂O to produce one mole of Ca(OH)₂

Therefore, 0.036 moles of CaO will produce 0.036 moles of Ca(OH)₂

Mass = Number of moles × Molar mass

The mass of 0.036 moles of Ca(OH)₂ ≈ 0.036 moles × 74.093 g/mol = 2.667348 grams

∴ The theoretical yield of Ca(OH)₂ = 2.667348 grams

Percentage \ yield = \dfrac{Actual \ yield}{Theoretical \ yield}  \times 100 \%

The percentage yield = (2.14 g)/(2.667348 grams) × 100 = 80.23%

Therefore, the option which is closest is option d. 81.1.

5 0
3 years ago
The density of ethanol is 0.789 g/mL. If you need 460.0 g of ethanol for an experiment, how many milliliters would you measure o
4vir4ik [10]

Answer:

The volume is 583.02 mL

Explanation:

Given that the density is:-

\rho=0.789\ g/mL

The mass, m=460.0\ g

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Using the above expression to calculate the volume as:-

V=\frac{m}{\rho}

Applying the values to calculate the volume as:-

V=\frac{460.0\ g}{0.789\ g/mL}=583.02\ mL

<u>The volume is 583.02 mL.</u>

3 0
3 years ago
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