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3 years ago

What kinda of water movement helps the fishing industry

Chemistry

1 answer:

Eddi Din [679]3 years ago

5 0

Answer:

Upwelling is the natural process which brings cold, nutrient-rich water to the surface. A huge upwelling regularly occurs off the coast of Peru, which enjoys a large fishing industry as a result. Upwelling is a process in which currents bring deep, cold water to the surface of the ocean.

Explanation:

good luck

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How many oxygens are used per glucose molecule in glycolysis?

dimulka [17.4K]

Answer:

Explanation:

7 0

1 year ago

Electrochemical processes are written with the oxidation half-reaction on the left and the reduction reaction on the right; wher

CaHeK987 [17]

Answer:

B) FALSE.

Explanation:

First off, its important to understand the following concepts;

A half reaction is either the oxidation or reduction reaction component of a redox (Oxidation - Reduction) reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

Often, the concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).

Half equations simply much just breaks the reaction into oxidation and reduction steps (irrespective of the order, whether left or right).

An example of half equation is given below;

Mg → Mg2+ + 2e− (Oxidation)

Cu2+ + 2e− → Cu (Reduction)

The answer is false because; oxidation-reduction reactions are NOT represented by equations that group the reaction participants into reactants and products. Rather they are

8 0

3 years ago

In order to study hydrogen halide decomposition, a researcher fills an evacuated 1.11 L flask with 0.822 mol of HI gas and allow

Elza [17]

Answer:

Kc = 168.0749

Explanation:

2HI(g) ↔ H2(g) + I2(g)

initial mol: 0.822 0 0

equil. mol: 2(0.822 - x) x x

∴ [ HI ]eq = 0.055 mol/L = 2(0.822 - x) / (1.11 L )

⇒ 1.644 - 2x = 0.055 * 1.11

⇒ 1.644 = 2x + 0.06105

⇒ 2x = 1.583

⇒ x = 0.7915 mol equilibrium

⇒ [ H2 ] eq = 0.7915mol / 1.11L = 0.7130 M = [ I2 ] eq

⇒ Kc = ([ H2 ] * [ I2 ]) / [ HI ]²

⇒ Kc = ( 0.7130² ) / ( 0.055² )

⇒ Kc = 168.0749

4 0

3 years ago

Flat coke is an example of

kozerog [31]

Chemical change? Need more context.

6 0

2 years ago

Read 2 more answers

A concentration cell consisting of two hydrogen electrodes (PH2 = 1 atm), where the cathode is a standard hydrogen electrode and

Lunna [17]

The pH of the unknown solution is 3.07.

Explanation:

1.Find the cell potential as a function of pH

From the Nernst Equation:

Ecell=E∘cell−RT /zF × lnQ

where

R denotes the Universal Gas Constant

T denotes the temperature

z denotes the moles of electrons transferred per mole of hydrogen

F denotes the Faraday constant

Q denotes the reaction quotient

Substitute the values,

E∘cell=0 lnQ=2.303logQ

E0cell=−2.30/RT /zF × log Q

Solving the equation,

2. Find the Q value

Q=[H+]2prod pH₂, product/ [H+]2reactpH₂, reactant

Q=[H+]^2×1/1×1=[H+]2

Taking the log

logQ= log[H+]^2=2log[H+]=-2pH

From the formula,

Ecell=−2.303RT /zF× logQ

E cell= 2.303 × 8.314 CK mol (inverse) × 298.15

K × 2pH /2×96 485 C⋅mol

( inverse)

E cell= 0.0592 V × pH

3. Finding the pH value

E cell= 0.0592 V × pH

pH = E cell/ 0.0592 V= 0.182V/ 0.0592V

pH=3.07

The pH of the unknown solution is 3.07.

7 0

3 years ago