Concentration of vinegar sample of 28mL which requires 21. 5 ml of 0.550 M NaOH to reach the endpoint in a titration is 0.42M.
<h3>How do we calculate the concentration of Vinegar?</h3>
Concentration of vinegar in the titration method will be used by using the below equation:
M₁V₁ = M₂V₂,
- M₁ & V₁ are the molarity and volume of acetic acid.
- M₂ & V₂ are the molarity and volume of vinegar sample.
By putting values on above equation from the question, we get
M₂ = (0.55M)(21.5mL) / (28mL) = 0.42 M
Hence, required concentration of vinegar is 0.42M.
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Answer:
When the substance is cooled, its temperature will fall below 80 °C after 100% of the liquid has changed to solid.
Explanation:
Melting point is the temperature at which a solid changes state to liquid. At the melting point, the phase of matter changes from solid state to a liquid flowing state.
If after a substance is cooled, without reaching its melting point, it will still remain as a liquid. Below the melting point the substance will freeze back to its solid state.
- For our hypothetical substance whose melting point is 80 °C, it implies that at this temperature, the substance undergoes a phase change from solid to liquid completely.
- The reverse is also the case, below the melting temperature, all parts of the compound changes back to its original solid state.
The compound form from propanoic acid and
dimethylamine is 3-(dimethylamino)propanoic acid. Propanoic acid is a liquid
carboxylic acid that has pungent and unpleasant smell resembling to body odor.
Its chemical formula is C2H5C00H. Moreover, dimethylamine is an organic
compound and a secondary amine that is colorless, flammable gas with an ammonia
like odor. Its chemical formula is (CH3)2NH.
The 2D structure is attached here.
Answer:
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The mass of ore required is
21 700 t.
r = 750 cm
V =
=
= 1.767 × 10⁹ cm³
The density of lead is 11.34 g/cm³.
So mass of lead sphere = 1.767 × 10⁹ cm³ ×
= 2.004 ×10¹⁰ g
2.004 ×10¹⁰ g ×
= 2.004 × 10⁷ kg
2.004 × 10⁷ kg ×
= 2.004 × 10⁴ t
92.5% efficiency means 92.5 t Pb per 100 t of ore.
Mass of ore = 2.004 × 10⁴ t Pb ×
= 2.17 × 10⁴ t ore = 21 700 t ore
