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2 years ago

What is an internal cost of driving a domestic car?

Chemistry

1 answer:

Nataly_w [17]2 years ago

3 0

Answer:

The correct option is: Cost of materials used in manufacture

Explanation:

There are two types of costs of an object: the internal costs and the external costs.

The internal cost of an object is the direct monetized cost. It refers to the cost involved in the production or manufacturing of a given object. Example: labor, material required, equipment, energy, and overhead expenses.

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Because their particles move and bounce around more freely, gases typically have more _____ than liquids and solids.

Soloha48 [4]

Kinetic energy if it's based on temperature but potential energy is talking in terms of entropy

4 0

3 years ago

When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be

Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

$AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)$

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

Molarity = $\frac{\text{no. of moles}}{\text{volume in liter}}$

0.269 M = $\frac{\text{no. of moles}}{1.14 L}$

no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.307 mol = $\frac{mass}{143.32 g/mol}$

mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

8 0

2 years ago

The study of the interaction between animals and plants within a specific environment is called

sergij07 [2.7K]

Answer:

The study is called ecology

Explanation:

Mark as brainliest if I'm correct

8 0

3 years ago

Read 2 more answers

Using the periodic table, answer the following question..How many atoms of neon are in 0.378g of neon (a) 6.02 x 10²³ atoms (b)

zmey [24]

Answer:

B 1.87×10^-²

Explanation:

20.1797 g Neon = 1 mol

0.378 g Neon = y

(Cross multiply)

20.1797y= 0.378 x 1

(Make y the subject of the formula)

y = 0.878/ 20.1787

y = 0.0187317

y = 0.0187 approx

y = 1.87 x 10^-²

7 0

3 years ago

Read 2 more answers

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.650 M, [B] = 1.35 M, and [C] = 0.300 M. The fo

dimaraw [331]

Answer: The value of $K_c$ for given reaction is 0.465

Explanation:

We are given:

Initial concentration of A = 0.650 M

Initial concentration of B = 1.35 M

Initial concentration of C = 0.300 M

Equilibrium concentration of A = 0.550 M

Equilibrium concentration of B = 0.400 M

For the given chemical equation:

$A+2B\rightarrow C$

Initial: 0.65 1.35 0.30

At eqllm: 0.65-x 1.35-2x 0.30+x

Evaluating the value of 'x'

$0.650-x=0.550\\\\x=0.100$

So, equilibrium concentration of B = 1.35 - 2x = [1.35 - 2(0.100)] = 1.15 M

Equilibrium concentration of C = (0.30 + x) = (0.300 + 0.100) = 0.400 M

The expression of $K_c$ for above equation follows:

$K_c=\frac{[C]}{[A][B]^2}$

Putting values in above equation, we get:

$K_c=\frac{0.400}{0.650\times (1.15)^2}\\\\K_c=0.465$

Hence, the value of $K_c$ for given reaction is 0.465

7 0

3 years ago