Answer: Vitamins
Explanation:
they are nutrients that are made by living things
All of them are properties of compounds except III.
for I, compounds are chemically combined together, so to separate them, we must use chemical methods like electrolysis or applying heat. These requires large amount of energy.
For II, they're always fixed. For example, in water (H2O), the ratio of hydrogen and oxygen is always 1:8 in mass. If there's some extra added, the substance becomes mixture instead of compounds.
For IV, after you chemically combined elements or compounds together, their properties are completely different. For example, iron can be attracted to magnets, but iron II sulphide does not.
A because the outcome of this reaction exists a radical formed by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol serves as the ring substituent in this condition.
<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
- The methyl group exists moved to cytosine in the first step, and it exists then hydroxylated in the second stage.
- Thus, a transferase and an oxidoreductase exist as the two groups of enzymes needed.
<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
- Hydrogen bonding because the glucose's OH would create an H-bond with any disclosed polar side chains on a protein surface.
<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH?</h3>
- Only positively charged proteins can attach to a cation-exchange column, and this can only occur when the pH exists lower than the pI.
- Proteins A and B would both be positively charged at pH 7.0.
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<u>Answer:</u> The correct answer is Option c.
<u>Explanation:</u>
Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.
The value of standard Gibbs free energy is 0 for equilibrium reactions.
To calculate 
for the reaction, we use the equation:
where,
= standard entropy change of vaporization
= standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol (Conversion factor: 1 kJ = 1000 J)
T = temperature of the reaction = 353.3 K
Putting values in above equation, we get:
Hence, the correct answer is Option c.
