All categories

3 years ago

Which statement identifies the element arsenic?

Chemistry

2 answers:

insens350 [35]3 years ago

8 0

Answer : Option A) Atomic number of Arsenic is 33.

Explanation : Arsenic contains same number of protons in its atomic nucleus. In arsenic there are 33 protons found in the atomic nucleus. Hence, the atomic number will be 33. It has 5 valence electrons in its outermost shell, which is also called as valence shell. So, its valency becomes 5.

finlep [7]3 years ago

3 0

The anwer is (1). The atomic number of arsenic is 33.

You might be interested in

Which components of the apparatus affect its motion?

vodka [1.7K]

Answer:

An internal force acts between elements of the system. ... Only external forces affect the motion of a system, according to Newton's first ... Newton's second law states that a net force on an object is responsible for its ... Prior to manned space flights, rocket sleds were used to test aircraft, missile equipment, and physiological

Explanation:

5 0

3 years ago

If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

Schach [20]

<u>Answer:</u> The amount of water required to prepare given amount of salt is 398.4 mL

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

$0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL$

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

4 0

3 years ago

A solution of hydrochloric acid (HCl, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was

kati45 [8]

Answer:

0.1410 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

Next, the data obtained from the question. This include:

Volume of acid, HCl (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Concentration of base, NaOH (Cb) = 0.1020 M

Concentration of acid, HCl (Ca) =?

CaVa / CbVb = nA/nB

Ca × 25 / 0.1020 × 34.55 = 1/1

Ca × 25 / 3.5241 = 1/1

Cross multiply

Ca × 25 = 3.5241 × 1

Ca × 25 = 3.5241

Divide both side by 25

Ca = 3.5241 / 25

Ca = 0.1410 M

Therefore, the concentration of the acid, HCl is 0.1410 M

3 0

3 years ago

When sodium bonds with chlorine, what is the chlorine electron configuration like?A. any other halogenB. neonC. argonD. radon

Vika [28.1K]

Answer:

Explanation:

For sodium to bond with chlorine, it is through electrovalent bonding.

It means , one electron is transferred from the sodium to the chlorine.

Normally, chlorine has 17 electrons, by adding one , we get 18 electrons.

This is the number of electrons for Argon

5 0

3 years ago

In your own words can yall give me a example of air pollution/

raketka [301]

Sulfur dioxide is an example of air pollution.
It is the main component of acid rain. It is released into the air as a result of the burning of fossil fuels.

3 0

3 years ago

Read 2 more answers