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s2008m [1.1K]
3 years ago
15

Define "Homoglycan" and "Heteroglycan" and give an example of each

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

Polysaccharides, also known as glycans, are the polymers of carbohydrate. These polymers are composed of the monosaccharide monomeric units that are joined together by glycosidic bonds.  

A polysaccharide molecule composed of the same type of monosaccharide units is known as homopolysaccharide or homoglycan.

Example: Cellulose, glycogen, and cellulose.

Whereas, a polysaccharide molecule composed of more than type of monosaccharide is known as heteropolysaccharides or heteroglycans.

Examples: Hyaluronic acid and heparin

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Nuclear is the answer
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Is air homogeneous or heterogeneous?
ivolga24 [154]

Answer:  yes, Air is a homogeneous mixture of the gaseous substances nitrogen, oxygen, and smaller amounts of other substances. Salt, sugar, and substances dissolve in water to form homogeneous mixtures. A homogeneous mixture in which there is both a solute and solvent present is also a solution

Explanation:

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2 years ago
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Find the density of Liquid A: Liquid A: Mass-138g Volume – 100 mL.
nlexa [21]

Answer:

The answer is

<h2>1.38 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of liquid = 138 g

volume = 100 mL

The density of the liquid is

density =  \frac{138}{100}  = \frac{69}{5 0}

We have the final answer as

<h3>1.38 g/mL</h3>

Hope this helps you

7 0
3 years ago
Pls help me in this:(​
antiseptic1488 [7]

Answer:

a) 26.98

b) 3

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d) 3 *16 = 48

e) 26.98 + 3.03 + 48 = 78.01

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3 0
3 years ago
A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.
likoan [24]

Given :

A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.

To Find :

The volume of the gas after it is heated.

Solution :

Since, their is no information about pressure in the question statement let us assume that pressure is constant.

Now, we know by ideal gas equation at constant pressure :

\dfrac{V_1}{V_2} = \dfrac{T_1}{T_2}\\\\\dfrac{3.82}{V_2}= \dfrac{204.9}{304.8}\\\\V_2 = \dfrac{304.8}{204.9} \times 3.82\\\\V_2 = 5.68 \ L

Hence, this is the required solution.

3 0
3 years ago
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