Answer:
You have to graph and label the points
Step-by-step explanation:
3x-5 is just a straight line which is lesser than or equal to -1 so that is a closed circle
-2x+3 is another straight line which is (both open circle) which its domain is restricted from -1 to 4
2 is just a horizontal line starting at (closed circle) 4, it is greater than also.
If you don't understand the the constants (the numbers on their own) just a vertical translation.
If the cross either the x or y axis, you have to find that too, im pretty sure.
To find the y axis intercept, make x = 0 and solve for y
and to find the x axis intercept, make y = 0 and solve for x
A)
Withdraws--5.23, -5.22, and -7.89
Deposits-34.98, 51.02, and 51.22
(Rational numbers include integers, whole numbers, decimals that don't repeat or go on forever, and fractions)
B)
-7.89, -5.23, -5.22, 34.98, 51.02, 51.22
(Negatives are less than 0, so when the negative gets bigger, it means that the number is becoming less, so the opposite of positive numbers)
C)
98+34.98+51.02+51.22= 235.22
235.22- 5.22-5.23-7.89= 216.88
216.88 is the answer
(since withdraws are subtracting from the total, you want to add up all of the positive numbers so the deposits plus the amount she had in the beginning, and then subtract the withdraws)
Hope this helps!
Answer:
a)2*(15-s) mi
b)30mi
c) 30 mi
Step-by-step explanation:
Answer:
Before and after current era
We know that Sum of Angles in a Triangle is Equal to 180°
Here EBF is a Triangle
⇒ m∠EBF + m∠BEF + m∠EFB = 180°
⇒ 60° + 40° + m∠EFB = 180°
⇒ 100° + m∠EFB = 180°
⇒ m∠EFB = 180° - 100°
⇒ m∠EFB = 80°
As Line m and Line p are Parallel Lines :
Alternate Interior Angles are Equal, here Alternate Interior Angles are m∠BEF and m∠ABE
⇒ m∠BEF = m∠ABE
⇒ m∠ABE = 40°
We know that Vertically Opposite Angles are Equal, Here m∠GFI and m∠EFB are Vertically Opposite Angles.
⇒ m∠GFI = m∠EFB
⇒ m∠GFI = 80°
We can notice that m∠DEB and m∠BEF form a Linear Pair
⇒ m∠DEB + m∠BEF = 180°
⇒ m∠DEB + 40° = 180°
⇒ m∠DEB = 180° - 40°
⇒ m∠DEB = 140°
We can notice that Sum of Angles m∠CBF and m∠EBF and m∠ABE is 180°
⇒ m∠CBF + m∠EBF + m∠ABE = 180°
⇒ m∠CBF + 60° + 40° = 180°
⇒ m∠CBF + 100° = 180°
⇒ m∠CBF = 180° - 100°
⇒ m∠CBF = 80°
We can notice that m∠BFG and m∠EFB form a Linear Pair
⇒ m∠BFG + m∠EFB = 180°
⇒ m∠BFG + 80° = 180°
⇒ m∠BFG = 180° - 80°
⇒ m∠BFG = 100°
We know that Vertically Opposite Angles are Equal, Here m∠BFG and m∠IFE are Vertically Opposite Angles.
⇒ m∠BFG = m∠IFE
⇒ m∠IFE = 100°
