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timurjin [86]
3 years ago
9

7•9=9•7 identify the property shown

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

Commutative Property of Multiplication

Step-by-step explanation:

This property states that two numbers can be multiplied in different orders as long as they are the same numbers as the original multiplication problem.

You might be interested in
Simplify (9 + 8 – 6)(4 – 5).
Temka [501]

Answer:

The answer would be - 11.

Step-by-step explanation:

9 + 8 = 17

17 - 6 = 11.

4 - 5 = 4 + - 5 = - 1

11(- 1) = 11 × - 1 = - 11

Therefor, your answer would be - 11.

Hope this helps!

5 0
3 years ago
Read 2 more answers
1. The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest
olga_2 [115]

Answer:

a)

$2.79 per pound.

$0.93 per apple.

b)

Unit price per pound is typically used because weight and size of every      apple is not same.

Step-by-step explanation:

5 pound bag of organic apples = $13.95

1 pound bag of organic apples = $13.95/5

                                                   = $2.79

The unit price of apples that cost $13.95 for 5 pounds is $12.79 per pound.

<em>As a general rule, 1 pound of apples is equal to: 4 small apples. 3 medium apples. 2 large apples. So, here we assume that apples are of medium size.</em>

3 apples cost = $2.79

<em>The unit price means 'what is the cost of 1 apple'</em>

1 apple cost    =$2.79/3

                       =$0.93

The unit price of apples that cost $2.79 for 3apples is $0.93 per apple.

<em />

4 0
3 years ago
Read 2 more answers
Stephanie puts 30 cubes in a box. each cube is 1/2 an inch on each side. The box holds 2 layers of 15 cubes. what is the volume
Serhud [2]

Answer:

3.75 cubic inches

Step-by-step explanation:

Volume = length x breadth x height

since the box holds 2 layers of 15 cubes

length contains 5 cubes= 5x1/2 inches=2.5 inches

breadth contains 3 cubes=3x1/2inches=1.5 inches

height contains 2 cubes=2x1/2inches=1.0 inches

Volume=2.5x1.5x1.0=3.75 cubic inches

5 0
3 years ago
The acceleration, in meters per second per second, of a race car is modeled by A(t)=t^3−15/2t^2+12t+10, where t is measured in s
oksian1 [2.3K]

Answer:

The maximum acceleration over that interval is A(6) = 28.

Step-by-step explanation:

The acceleration of this car is modelled as a function of the variable t.

Notice that the interval of interest 0 \le t \le 6 is closed on both ends. In other words, this interval includes both endpoints: t = 0 and t= 6. Over this interval, the value of A(t) might be maximized when t is at the following:

  • One of the two endpoints of this interval, where t = 0 or t = 6.
  • A local maximum of A(t), where A^\prime(t) = 0 (first derivative of A(t)\! is zero) and A^{\prime\prime}(t) (second derivative of \! A(t) is smaller than zero.)

Start by calculating the value of A(t) at the two endpoints:

  • A(0) = 10.
  • A(6) = 28.

Apply the power rule to find the first and second derivatives of A(t):

\begin{aligned} A^{\prime}(t) &= 3\, t^{2} - 15\, t + 12 \\ &= 3\, (t - 1) \, (t + 4)\end{aligned}.

\displaystyle A^{\prime\prime}(t) = 6\, t - 15.

Notice that both t = 1 and t = 4 are first derivatives of A^{\prime}(t) over the interval 0 \le t \le 6.

However, among these two zeros, only t = 1\! ensures that the second derivative A^{\prime\prime}(t) is smaller than zero (that is: A^{\prime\prime}(1) < 0.) If the second derivative A^{\prime\prime}(t)\! is non-negative, that zero of A^{\prime}(t) would either be an inflection point (ifA^{\prime\prime}(t) = 0) or a local minimum (if A^{\prime\prime}(t) > 0.)

Therefore \! t = 1 would be the only local maximum over the interval 0 \le t \le 6\!.

Calculate the value of A(t) at this local maximum:

  • A(1) = 15.5.

Compare these three possible maximum values of A(t) over the interval 0 \le t \le 6. Apparently, t = 6 would maximize the value of A(t)\!. That is: A(6) = 28 gives the maximum value of \! A(t) over the interval 0 \le t \le 6\!.

However, note that the maximum over this interval exists because t = 6\! is indeed part of the 0 \le t \le 6 interval. For example, the same A(t) would have no maximum over the interval 0 \le t < 6 (which does not include t = 6.)

4 0
3 years ago
dina called her friend to tell her that she saved 30% on her new skirt at a discount store. Her friend told her that she could h
Triss [41]

Answer:

She could have saved 1.8 more dollars.

Step-by-step explanation:

30% is the same as 0.3. 0.3 times 54$ is 16.2$. 1/3 times 54$ is 18$. 18$ - 16.2$ is 1.8$.

4 0
2 years ago
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