Which is not an improper fraction equal to eight

Mathematics

2 answers:

Oliga [24]3 years ago

7 0

The fraction that is improper and it equals 8 is 64/8

Nady [450]3 years ago

6 0

It would be 64/8 hope that helped

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F(x) = x + 2 g(x) = x – 4 (f g)(x) =

Sauron [17]

Answer:

x² - 2x - 8

Step-by-step explanation:

The notation (f·g)(x) means to multiply the two functions. Use the distributive property to simplify.

(f·g)(x) = (x+2)(x-4) = x² + 2x - 4x - 8 = x² - 2x - 8

4 0

3 years ago

Read 2 more answers

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago

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IgorC [24]