Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
thirty
Step-by-step explanation:
The answer to the question is A
Answer:

Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference
we have

Let



The common difference is 
We can write an Arithmetic Sequence as a rule

where
a_n is the nth term
d is the common difference
a_1 is the first term
n is the number of terms
Find the 63rd term of the arithmetic sequence
we have

substitute




Answer:
Gene ran faster
Step-by-step explanation:
The fastest time is the smallest time since they ran the same distance
gene ran 90 meters in 16.3 seconds.
alma ran 90 meters in 17.2 seconds
16.3 < 17.2
Gene ran faster