Which statement is true of a chemical change?

2 answers:

5 0

The appropriate answer is a. it involves a change in the molecular structure of the substance. A change in phase or state is referred to as a physical change. For example...liquid water freezing is a physical change because the state changes but solid water is still H20. Separating water into its constituent atoms, hydrogen and oxygen is a chemical change because the molecular structure of water is now non existent.

tatiyna4 years ago

4 0

The answer is c. There wouldnt be a process or a change to it

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Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c

Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

$m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO} *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2$

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

$Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%$

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m_a_m_a [10]

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I Think it might be A! I hope I am right!

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How many kilojoules are required to convert 115.0 g of ice at 0.0 ∘c to liquid water at 32 ∘c? the heat of fusion of water is 33

Ivanshal [37]

The answer is 53.8 kJ.
Solution:There are two major steps in converting ice to liquid water. It begins with a phase change when ice melts at 0.0°C, and then a temperature change when the liquid water rises in temperature from zero to 32°C.
The amount of heat involved with the phase change melting is given by
q = (mass of water) (ΔHfus)
= (115.0 g)(334 J/g)
= 38410 J = 38.41 kJ
The amount of heat involved with temperature change is
q = mcΔT
= (115.0g)(4.184J/g°C)(32°C - 0.0°C)
= 15397.12 J = 15.39712 kJ
Summing up the two values gives the total heat required to convert ice to liquid water:
q = 38.41 kJ + 15.39712 kJ= 53.8 kJ

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