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nika2105 [10]
3 years ago
11

Resistance is caused by _________________in a current bumping into electrons and ions in the matter through which the current is

flowing.
electrons


matter


protons


neutrons
Chemistry
1 answer:
zysi [14]3 years ago
8 0
The answer is protons
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What information does a solubility table give?
guajiro [1.7K]

Answer:

Option D - It tells which compounds will dissolve in water.

Explanation:

It is used to predict whether or not a given ionic compound is soluble.

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2 years ago
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What is waste good for?
harkovskaia [24]
A because that honestly just makes the most sense
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What is the molarity of a solution made by dissolving 8.60 g of a solid with a
Dima020 [189]

Answer:

1.43 M

Explanation:

We'll begin by calculating the number of mole of the solid. This can be obtained as follow:

Mass of solid = 8.60 g

Molar mass of solid = 21.50 g/mol

Mole of solid =?

Mole = mass / molar mass

Mole of solid = 8.60 / 21.50

Mole of solid = 0.4 mole

Next, we shall convert 280 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

280 mL = 280 mL × 1 L / 1000 mL

280 mL = 0.28 L

Thus, 280 mL is equivalent to 0.28 L.

Finally, we shall determine the molarity of the solution. This can be obtained as illustrated below:

Mole of solid = 0.4 mole

Volume = 0.28 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.4 / 0.28

Molarity = 1.43 M

Thus, the molarity of the solution is 1.43 M.

8 0
3 years ago
What type of potential energy do fuels contain
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Kinetic energy maybe or something
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3 years ago
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Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium woul
nalin [4]

Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

A = A_{0} \times (\frac{1}{2})^{t/T}

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

A = A_{0} \times (\frac{1}{2})^{t/T}

   = 0.50 \times (\frac{1}{2})^{60/11.6}

   = 0.50 \times (\frac{1}{2})^{5.17}

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

3 0
1 year ago
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