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trasher [3.6K]
2 years ago
7

Working principles of lithium/solid electrolytes batteries​

Chemistry
1 answer:
saw5 [17]2 years ago
8 0

Answer:

The electrolyte carries positively charged lithium ions from the anode to the cathode and vice versa through the separator. The movement of the lithium ions creates free electrons in the anode which creates a charge at the positive current collectors

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To which group of the periodic table do lithium and potassium belong?
s344n2d4d5 [400]

Answer:

1)alkali metals

2)1g/ml

3) mercury

Explanation:

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6 0
2 years ago
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35. Which of the following atoms has the most possible bond sites?
Vadim26 [7]

Answer:

C phosphorus has 5 bond sites.

4 0
3 years ago
The density of air at ordinary atmospheric pressure and 25 ∘C is 1.19 g/L. What is the mass, in kilograms, of the air in a room
marshall27 [118]
Given:
The density of air = 1.19 g/L at 25°C and atmospheric pressure,
or
density = 1.19 x 10⁻³ kg/L

Volume of air in the room is
V = 12.5*19.5*6.0 = 1462.5 ft³

Note that
1 ft³ = 28.317 L
Therefore
V = (1462.5 ft³)*(28.317 L/ft³) = 4.1414 x 10 ⁴ L

By definition, mass = density*volume.
Therefore, the mass is
(1.19 x 10⁻³ kg/L)*(4.1414 x 10⁴ L) = 49.283 kg

Answer: 49.3 kg (nearest tenth)
7 0
3 years ago
A student obtained 2.00 g of pure caffeine following recrystallization from a crude sample, which originally weighed 2.56 g. Wha
Lady_Fox [76]

Answer: 78.125%

Explanation:

From the question, we are informed that a student obtained 2.00g of pure caffeine following recrystallization from a crude sample, which originally weighed 2.56g.

The percent recovery of pure caffeine from crude will be calculated as:

= Mass of pure caffeine / Mass of crude sample × 100

= 2.00 / 2.56 × 100

= 78.125%

7 0
3 years ago
1) 14.7 moles of Au react, how many grams of Au will that be?
lawyer [7]
<h3>Answer:</h3>

2900 g Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 14.7 mol Au

[Solve] g Au

<u>Step 2: Identify Conversion</u>

[PT] Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 14.7 \ mol \ Au(\frac{196.97 \ g \ Au}{1 \ mol \ Au})
  2. [DA] Multiply [Cancel out units]:                                                                     \displaystyle 2895.46 \ g \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2895.46 g Au ≈ 2900 g Au

6 0
3 years ago
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