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3 years ago

What factors affect water quality?

Physics

1 answer:

JulsSmile [24]3 years ago

3 0

Answer:

Explained below:

Explanation:

Water quality is determined in terms of the physical, chemical and biological content of water. The quality of water of lakes and rivers variates with the seasons and also geographic areas, still in the absence of pollution. There are so many factors which affect water quality are as follows :

Pesticides

Temperature

Runoff

Sedimentation

Erosion

Dissolved oxygen

Pesticides

Litter and rubbish

Decayed organic materials

Toxic and hazardous substances

Oils, grease, and other chemicals

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Two boys (same height) are standing on a bridge each boy throws a rock straight down into the river below. they throw the rock a

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Perhaps one threw it at a greater velocity?

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Ad libitum [116K]

Answer:

9.66E4 J

Explanation:

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3 years ago

suppose that the man pictured on the front side is orbiting the earth (mass=5.98 x 10^24kg at a distance of 310 miles above the

wlad13 [49]

Answer:

a = 9.81[m/s^2]; v = 18683.5[m/s]

Explanation:

The stament of the problem is:

Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).

a. What acceleration does he experience due to the earth's pull?

b. What tangential velocity must he possess in order that he orbit safely (in m/s)?

First we need to convert all the initial data to units of the SI

Rs = 310 [mil] = 498897 [m]

RT= 400 [mil] = 643738 [m]

r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"

$F=G*\frac{M*m}{r^{2} } \\where:\\$

G = universal gravitational constant

M = mass of the earth [kg]

m = mass of the man [kg]

r = distance from the center of the earth to the man [m]

The acceleration he is experimenting is the same acceleration given by the gravity, therefore:

a = g = 9.81[m/s^2]

To find the tangential velocity, we must determinate the force exerted by the earth.

Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.

$G = 6.67*10^{-11} [\frac{N*m^{2} }{kg^{2} } ]\\M=5.98*10^{24}[kg]\\ m=100 [kg]\\Replacing:\\F = G*\frac{M*m}{r^{2} }$

$F = 6.67*10^{-11}*\frac{5.98*10^{24}*100 }{1142635^{2} } \\ F= 30550 [N]$

And this force will be equal to the following expression:

$F = m*\frac{v^{2} }{r} \\where:\\v= tangential velocity [m/s]\\v=\sqrt{\frac{F*r}{m} } \\v=\sqrt{\frac{30550*1142635}{100} } \\v=18683.5[m/s]$

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3 years ago

How do the magnitudes of the inertial (the density times acceleration term), pressure, and viscous terms in the Navier-Stokes eq

Troyanec [42]

Answer:

The general equation of movement in fluids is obtained from the application, at fluid volumes, of the principle of conservation of the amount of linear movement. This principle establishes that the variation over time of the amount of linear movement of a fluid volume is equal to that resulting from all forces (of volume and surface) acting on it. Expressed in This equation is called the Navier-Stokes equation.

The equation is shown in the attached file

Explanation:

The derivative of velocity with respect to time determines the change in the velocity of a particle of the fluid as it moves in space. It also includes convective acceleration, expressed by a nonlinear term that comes from convective inertia forces). With this equation, Stokes studied the motion of an infinite incompressible viscous fluid at rest at infinity, and in which a solid sphere of radius r makes a rectilinear and uniform translational motion of velocity v. It assumes that there are no external forces and that the movement of the fluid relative to a reference system on the sphere is stationary. Stokes' approach consists in neglecting the nonlinear term (associated with inertial forces due to convective acceleration).

Download pdf

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4 years ago

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Vsevolod [243]

Answer: D) none of the above

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Option A) can be ruled out since no matter how much friction is reduced, it will always exist and therefore some energy will be lost

option B) and C) are out of context since the loss of work or energy will continue to exist even if those values are modified, so they do not answer the question

D) is the correct one since it should be said that this is not possible (so far...) as it goes against the conservation of energy and this option is none of the above

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2 years ago