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MatroZZZ [7]
3 years ago
5

What factors affect water quality?

Physics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

Explained below:

Explanation:

Water quality is determined in terms of the physical, chemical and biological content of water. The quality of water of lakes and rivers variates with the seasons and also geographic areas, still in the absence of pollution. There are  so many factors  which affect water quality are as follows :

Pesticides

Temperature

Runoff

Sedimentation

Erosion

pH

Dissolved oxygen

Pesticides

Litter and rubbish

Decayed organic materials

Toxic and hazardous substances

Oils, grease, and other chemicals

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How can you increase the intensity of sound waves
VladimirAG [237]

Answer

The intensity of a sound wave depends on the pressure of the wave,density of the medium and speed of sound in the medium. Higher density and higher sound speed both give a lower intensity. and may be it is because that sound wave is more characterize by wavelength than frequency..explanation

Explanation:

As decibel levels get higher, sound waves have greater intensity and sounds are louder. For every 10-decibel increase in the intensity of sound, loudness is 10 times greater. Intensity of sound results from two factors: the amplitude of the sound waves and how far they have traveled from the source of the sound.

5 0
3 years ago
Luigi twirls a round piece of pizza dough overhead with a frequency of
viva [34]

The linear speed of the pepperoni is 0.628 m/s. Its direction is tangential to the circle.

We know that;

v = rω

r = radius of the piece = 10 cm or 0.1 m

ω = angular velocity

We have to convert 60 revolutions per minute to radians per second

1 rev/min = 0.10472 rad/s

60 revolutions per minute = 60 rev/min × 0.10472 rad/s/1 rev/min

= 6.28 rad/s

v =  0.1 m ×  6.28 rad/s

v = 0.628 m/s

The direction of this velocity is tangential to the circle.

Learn more: brainly.com/question/4612545

5 0
2 years ago
A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
Evgen [1.6K]

Answer:

\dfrac{d\theta}{dt}=0.038\ rad/s

Explanation:

Given that

\dfrac{dx}{dt}= -1\ m/s

From the diagram

tan\theta=\dfrac{21}{x}

By differentiating with time t

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

When x= 10 m

tan\theta=\dfrac{21}{10}

θ = 64.53°

Now by putting the value in equation

sec^2\theta \dfrac{d\theta}{dt}=-\dfrac{21}{x^2}\dfrac{dx}{dt}

sec^264.53^{\circ} \dfrac{d\theta}{dt}=-\dfrac{21}{10^2}\times (-1)

\dfrac{d\theta}{dt}=0.038\ rad/s

Therefore rate of change in the angle is 0.038\ rad/s

8 0
3 years ago
A 65.0-kg runner has a speed of 5.20 m/s at one instant dur- ing a long-distance event. (a) What is the runner’s kinetic energy
vladimir2022 [97]

Answer:

a)KE=878.8 J

b)W=2636.4 J      

Explanation:

Given that

mass ,m = 65 kg

Initial speed ,u = 5.2 m/s

a)

We know that kinetic energy KE is given as follows

KE=\dfrac{1}{2}mu^2

m=mass

u=velocity

Now by putting the values in the above equation we get

KE=\dfrac{1}{2}\times 65\times 5.2^2\ J

KE=878.8 J

b)

We know that

Work done by all forces = Change in the kinetic energy

The final velocity , v= 2 u = 2 x 5.2 m/s

v= 10.4 m/s

W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

Now by putting the values in the above equation we get

W=\dfrac{1}{2}\times 65\times 10.4^2-\dfrac{1}{2}\times 65\times 5.2^2\ J

W=2636.4 J

a)KE=878.8 J

b)W=2636.4 J

8 0
3 years ago
A current of 12 A flows for 20 minutes into an electric cooker. How much charge has the cooker used?
cluponka [151]
Time= 20 minutes= 20*60=1200 s
Charge=current*time=12*1200=14400 C
7 0
3 years ago
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