The frequency of a simple harmonic oscillator such as a spring-mass system is given by
![f= \frac{1}{2 \pi} \sqrt{ \frac{k}{m} }](https://tex.z-dn.net/?f=f%3D%20%5Cfrac%7B1%7D%7B2%20%5Cpi%7D%20%20%20%5Csqrt%7B%20%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20)
where
k is the spring constant
m is the mass attached to the spring.
Re-arranging the formula, we get:
![m= \frac{k}{4 \pi^2 f^2}](https://tex.z-dn.net/?f=m%3D%20%5Cfrac%7Bk%7D%7B4%20%5Cpi%5E2%20f%5E2%7D%20)
and since we know the constant of the spring:
![k=39.5 N/m](https://tex.z-dn.net/?f=k%3D39.5%20N%2Fm)
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
Haven't taken physics but I would assume if her friend is standing in front of her that you would add up the speeds and get 30 km/hr.
Answer:
The center of mass of the two-ball system is 7.05 m above ground.
Explanation:
<u>Motion of 0.50 kg ball:</u>
Initial speed, u = 0 m/s
Time = 2 s
Acceleration = 9.81 m/s²
Initial height = 25 m
Substituting in equation s = ut + 0.5 at²
s = 0 x 2 + 0.5 x 9.81 x 2² = 19.62 m
Height above ground = 25 - 19.62 = 5.38 m
<u>Motion of 0.25 kg ball:</u>
Initial speed, u = 15 m/s
Time = 2 s
Acceleration = -9.81 m/s²
Substituting in equation s = ut + 0.5 at²
s = 15 x 2 - 0.5 x 9.81 x 2² = 10.38 m
Height above ground = 10.38 m
We have equation for center of gravity
![\bar{x}=\frac{m_1x_1+m_2x_2}{m_1+m_2}](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7Bm_1x_1%2Bm_2x_2%7D%7Bm_1%2Bm_2%7D)
m₁ = 0.50 kg
x₁ = 5.38 m
m₂ = 0.25 kg
x₂ = 10.38 m
Substituting
![\bar{x}=\frac{0.50\times 5.38+0.25\times 10.38}{0.50+0.25}=7.05m](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B0.50%5Ctimes%205.38%2B0.25%5Ctimes%2010.38%7D%7B0.50%2B0.25%7D%3D7.05m)
The center of mass of the two-ball system is 7.05 m above ground.
Answer: it can be considered a genetic mutation with a history of a Golden Retriever in their blood but it is very rare. and there our some black retrievers you can buy too. i hope i helped
Explanation:
Answer: To answer this question, we will need the following equation: SPEED = DISTANCE/TIME (A multiplication and division triangle will be shown)i) The speed of the car is calculated by doing 100 metres/ 20 seconds which gives us 5 metres per second. ii) Rearranging the equation earlier, we can make the distance the subject of the equation so that we get SPEED x TIME = DISTANCE. We worked out the speed and the time was given as 1 minute 40 seconds but we cannot plug in the numbers yet as the time has to be converted to units of seconds (because our speed is in meters per second). 1 minute 40 seconds = 60 seconds + 40 seconds = 100 secondsWe then plug in the numbers to get the distance travelled = 5 metres per second x 100 seconds = 500 metres.
Explanation: