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3 years ago

13

If the rocket launches with a force of 10N, what is the force on the launch pad?

1 answer:

ser-zykov [4K]3 years ago

5 0

Answer:

10N

Explanation:

Action and Reaction forces state that the force will be equal

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WILL GIVE BRAINLIEST!!!

vovikov84 [41]

Answer:

D.

boulder-sized rocks that come from the asteroid belt

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3 years ago

How to find initial velocity

lesya [120]

Answer:

Velocity is a function of time and defined by both a magnitude and a direction. [1] Often in physics problems, you will need to calculate the initial velocity (speed and direction) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the information given in a problem, you can determine the proper equation to use and easily answer your question.

Explanation:

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7 0

3 years ago

Which of the following is not a an example of dissipated energy?

Kaylis [27]

Which of the following is not a an example of dissipated energy?
b. kinetic

When energy is changed from one form to another, ____.

b. all of the energy can be accounted for

4 0

3 years ago

In a lab experiment a light flexible string is wrapped around a solid cylinder with mass M = 9.50 kg and radius R. The cylinder

Lunna [17]

Answer: $3.79 m/s^2$

Explanation:

Given

Mass $M=9.5 kg$

$m=3 kg$

Net Force is equivalent to $\sum F=ma$

with tension T in the string

For mass $m$

$mg-T=ma$

$T=mg-ma--------1$

For cylinder

$T\cdot R=I\times \alpha$

I for solid cylinder is $\frac{2}{5}MR^2 , and \alpha =\frac{a}{R}$

thus $T=\frac{Ma}{2}----2$

Substitute the value of T we get

$\frac{Ma}{2}=mg-ma$

$a(\frac{M}{2}+m)=mg$

$a=\frac{mg}{\frac{M}{2}+m}$

$a=3.79 m/s^2$

5 0

3 years ago

A circuit containing an inductor and a capacitor in series is designed to have a resonant frequency of 4511 Hz. If the inductor

OLEGan [10]

Answer:

(e) $6.835\times 10^{-7}F$

Explanation:

At resonance we know that $X_l=X_C$

That is $\omega L=\frac{1}{\omega C}$

$\omega ^2=\frac{1}{LC}$

$\omega =\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

We have given resonance frequency f =4511 Hz and inductance L=1.82 mH

So $4511=\frac{1}{2\pi \sqrt{LC}}$

$LC=\frac{1}{4\pi ^2\times 4511^2}$

$LC=1.244\times 10^{-9}$

$C=\frac{1.244\times 10^{-9}}{1.82\times 10^{-3}}=0.6835\times 10^{-6}=6.835\times 10^{-7}F$

So option e is the correct answer

3 0

3 years ago