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Mkey [24]
3 years ago
13

A bowling ball is dropped from rest. what is the ball’s velocity after falling for 4 seconds?

Physics
1 answer:
muminat3 years ago
4 0

Answer:

it would be 39.2 m/s

Explanation:

After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.

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CAN SOMEONE PLS HELP ME!!!
scZoUnD [109]

Answer:

c

Explanation:

the question answered itself.

4 0
2 years ago
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A cyclist rides 6.3 km east for 21 minutes, then he turns and heads west for 6 minutes and 1.8 km. Finally, he rides east for 13
Leona [35]

Answer:

\vec{d}=17.7km

Explanation:

Displacement is a vector that defines the position of a particle. The vector extends from the initial position to the final position. Therefore, the displacement only takes into account this positions, since its trajectory is not important:

\vec{d}=6.3km-1.8km+13.2km\\\vec{d}=17.7km

6 0
4 years ago
Kepler proposed the modern model of the solar system. <br> True or False
givi [52]

Answer:

True

Explanation:

Johannes Kepler was a German astronomer, mathematician and astrologer. He proposed a model of the solar system which remains in use, with some modifications. Moreover, he developed the laws of planetary motion which explain how the planets move around the sun. This work was not only significant on its own, but it also provided the foundations for Newton's theory of universal gravitation.

4 0
3 years ago
What element has 34 protons and 36 electrons
Strike441 [17]

Answer:

Selenium

Explanation:

8 0
4 years ago
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A satellite moves in a circular orbit at a constant speed v0 around Earth at a distance R from its center. The force exerted on
postnew [5]

Answer:

vT = v0/3

Explanation:

The gravitational force on the satellite with speed v0 at distance R is F = GMm/R². This is also equal to the centripetal force on the satellite F' = m(v0)²/R

Since F = F0 = F'

GMm/R² = m(v0)²/R

GM = (v0)²R  (1)

Also, he gravitational force on the satellite with speed vT at distance 3R is F1 = GMm/(3R)² = GMm/27R². This is also equal to the centripetal force on the satellite at 3R is F" = m(vT)²/3R

Since F1 = F'

GMm/27R² = m(vT)²/3R

GM = 27(vT)²R/3

GM = 9(vT)²R (2)

Equating (1) and (2),

(v0)²R = 9(vT)²R

dividing through by R, we have

9(vT)² = (v0)²

dividing through by 9, we have

(vT)² = (v0)²/9

taking square-root of both sides,

vT = v0/3

6 0
3 years ago
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