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stealth61 [152]
4 years ago
15

How is carbon dioxide absorbed by the ocean? Select all that apply.

Chemistry
1 answer:
stich3 [128]4 years ago
5 0
Plankton on the surface absorbs it from the atmosphere for photosynthesis. xxx
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The energy absorbed or released when a neutral atom loses one electron
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It is called an ion.
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3 years ago
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A child pulls a sled up a snow-covered hill. The child does 405 J of work on the sled. If the child walks 15 m up the hill, how
kondor19780726 [428]

Answer: I think the answer is 27N.

Explanation:

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3 years ago
In a coffee-cup calorimeter, 1.60 g of NH4NO3 was mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolu
jekas [21]

Answer:

Explanation:

mass of the solution m = 1.6 + 75 = 76.6 g

fall in temperature = 25 - 23.34 = 1.66°C

heat absorbed = mass x specific heat x fall in temperature

= 76.6 x 1.66 x 4.18

= 531.5 J .

= .5315 kJ .

mol weight of ammonium nitrate = 80 g

heat absorbed by 1.6 g = .5315 kJ

heat absorbed by 80 g or one mole = 26.575 kJ

enthalpy change ΔH = +26.575 kJ

b )

enthalpy of hydration = 2630 kJ / mol

lattice energy = enthalpy of hydration + enthalpy change

= 2630 + 26.575

= 2656.575 kJ  .

7 0
3 years ago
Miss White wants to make a (decidedly not poisoned) apple pie. The recipe she is
Rina8888 [55]
So you have to multiply 786,3 times 0.98 to get the mass the mass is 770.57 if u round its 770.6 or 771
5 0
3 years ago
Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.
valina [46]

Answer: The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 29.0°C

Final temperature of the water = T_f  = 46.0°C

Change in temperature ,\Delta T=T_f-T_i=(46.0-29.0)^0C=17.0^0C

Putting in the values, we get:

Q=7.40g\times 4.184J/g^0C\times 17.0^0C

Q=526J

The amount of heat energy in joules required to raise the temperature is 526 Joules

4 0
3 years ago
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