Answer:
22.45g of Fe will be produced
Explanation:
The balanced reaction is:
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)
<em>Where 1 mole of Iron (III) oxide reacts with 2 moles of Iron</em>
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To solve this question we have to find the moles of iron (III) oxide. With these moles and the balanced reaction we can find the moles of iron produced and its mass:
<em>Moles iron (III) oxide -Molar mass: 159.69g/mol-</em>
32.1g Fe₂O₃ * (1mol / 159.69g) = 0.201 moles Fe₂O₃
<em>Moles Iron:</em>
0.201 moles Fe₂O₃ * (2mol Fe / 1mol Fe₂O₃) = 0.402 moles of Fe
<em>Mass Fe -Molar mass: 55.845g/mol-</em>
0.402 moles of Fe * (55.845g/mol) =
<h3>22.45g of Fe will be produced</h3>
