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lakkis [162]
3 years ago
12

How many grams of solid iron will be produced from 32.1 grams of iron (III) oxide? Hint: Balance the equation first

Chemistry
1 answer:
Taya2010 [7]3 years ago
3 0

Answer:

22.45g of Fe will be produced

Explanation:

The balanced reaction is:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

<em>Where 1 mole of Iron (III) oxide reacts with 2 moles of Iron</em>

<em />

To solve this question we have to find the moles of iron (III) oxide. With these moles and the balanced reaction we can find the moles of iron produced and its mass:

<em>Moles iron (III) oxide -Molar mass: 159.69g/mol-</em>

32.1g Fe₂O₃ * (1mol / 159.69g) = 0.201 moles Fe₂O₃

<em>Moles Iron:</em>

0.201 moles Fe₂O₃ * (2mol Fe / 1mol Fe₂O₃) = 0.402 moles of Fe

<em>Mass Fe -Molar mass: 55.845g/mol-</em>

0.402 moles of Fe * (55.845g/mol) =

<h3>22.45g of Fe will be produced</h3>
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A certain chemical reaction releases 36.2 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Lilit [14]

Answer:

0.038 g of reactant

Explanation:

Data given:

Heat release for each gram of reactant consumption = 36.2 kJ/g

mass of reactant that release 1360 J of heat = ?

Solution:

As  36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J

As we know

1 KJ = 1000 J

So

36.2 kJ = 36.2 x 1000 = 36200 J

So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release

Apply unity formula

                 36200 J of heat release ≅ 1 gram of reactant

                 1360 J of heat release ≅ X gram of reactant

Do cross multiplication

              X gram of reactant = 1 g x 1360 J / 36200 J

              X gram of reactant = 0.038 g

So 0.038 g of reactant will produce 1360 J of heat.

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Chalcopyrite is an ore with the composition cufes2. what is the percentage of iron in a 39.6 g sample of this ore? answer in uni
iren2701 [21]
<span>Well it depends on percentage by what, but I'll just assume that it's percentage by mass. For this, we look at the atomic masses of the elements present in the compound. Cu has an atomic mass of 63.546 amu Fe has 55.845 amu and S has 36.065 amu Since there are 2 molecules of Sulfur for each one of Cu and Fe, we'll multiply the Sulfur atomic weight by 2 to obtain 72.13 amu So we have not established the mass of the compound in amus 63.546 + 55.845 + 72.13 = 191.521 That is the atomic mass of Chalcopyrite. and Iron's atomic mass is 55.845 So to get the percentage, or fraction of iron, we take 55.845 / 191.521 Which comes out to 29.15% by mass Mass of the sample is not needed for this calculation, but since the question mentions it I would go ahead and check if the question isn't also asking for the mass of Iron in the sample as well, in which case you just find the 29.15% of 67.7g</span>
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