Question

How many grams of solid iron will be produced from 32.1 grams of iron (III) oxide? Hint: Balance the equation first

Answer 1

Answer:

22.45g of Fe will be produced

Explanation:

The balanced reaction is:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

Where 1 mole of Iron (III) oxide reacts with 2 moles of Iron

To solve this question we have to find the moles of iron (III) oxide. With these moles and the balanced reaction we can find the moles of iron produced and its mass:

Moles iron (III) oxide -Molar mass: 159.69g/mol-

32.1g Fe₂O₃ * (1mol / 159.69g) = 0.201 moles Fe₂O₃

Moles Iron:

0.201 moles Fe₂O₃ * (2mol Fe / 1mol Fe₂O₃) = 0.402 moles of Fe

Mass Fe -Molar mass: 55.845g/mol-

0.402 moles of Fe * (55.845g/mol) =

22.45g of Fe will be produced