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alina1380 [7]
3 years ago
8

 The atom fluorine generally will become _____ stable through the formation of an ionic chemical compound by accepting _______ e

lectron(s) from another atom. This process will fill its outer energy level of electrons.
A)more, 1B)less, 1C)more, 2D)less, 2
Chemistry
2 answers:
fgiga [73]3 years ago
7 0

Answer:

more and 1

Explanation:

i just took the test :)

larisa86 [58]3 years ago
3 0

The atomic number of Fluorine is 9

Valence (outer) electron configuration is : 2s²2p⁵

Therefore, it requires 1 electron in the p-orbital to complete its octet of 8 electrons.

Thus, the atom Fluorine generally will become <u>more </u>stable through the formation of an ionic chemical compound by accepting <u>1 </u> electron from another atom. This process will fill its outer energy level.

Ans:  A) more, 1

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The correct answer is b. an element

The explanation:

when the ELEMENT is define as substance that cannot be decomposed (broken down) into simpler substances by ordinary chemical means. Examples: gold, iron, carbon, hydrogen, oxygen, nitrogen

Ex: diamond will be broken into carbon as well.

and SUBSTANCE: Material composed of only one kind of matter throughout (same atoms or same molecules).

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3 years ago
The combustion of how many moles of ethane (C2H6) would be required to heat 851 g of water from 25.0°C to 98.0°C? (Assume liquid
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Answer : The number of moles of ethane required will be 0.166 mole.

Explanation :

First we have to calculate the heat absorbed by water.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

m = mass of water = 851 g

c = specific heat of water = 4.18J/g^oC

T_{final} = final temperature = 98.0^oC

T_{initial} = initial temperature = 25.0^oC

Now put all the given values in the above formula, we get:

q=851g\times 4.18J/g^oC\times (98.0-25.0)^oC

q=259674.14J=259.67kJ         (1 kJ = 1000 J)

Now we have to calculate the moles of ethane required.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of ethane = 1560.7 kJ/mol (standard value)

q = heat absorbed = 259.67 kJ

n = number of moles of ethane = ?

1560.7kJ/mol=\frac{259.67kJ}{n}

n=\frac{259.67kJ}{1560.7kJ/mol}

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Therefore, the number of moles of ethane required will be 0.166 mole.

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