Answer:
There is 5.56 g of gold for every 1 g of chlorine
Explanation:
The question is to determine the simplest mass ratio of gold to Chlorine in the compound.
Since the mass of gold in the compound compared to chlorine is 15.39 g for every 2.77 g, the mass of gold per gram of chlorine is given as:
15.39 / 2.77 = 5.56 g of gold to two decimal places
<em>Therefore, for every 5.56 g of gold, there is 1 g of chlorine.</em>
<em>Note : The ratio in which different elements combine by mass to form a compound is given by the law of constant composition which states that, "all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass.</em>
Answer:
x = 33.52 amu
Explanation:
It is given that,
Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.
Let x is the average atomic mass of this element. It can be calculated as follows :
So, the average atomic mass of this element is 33.52 amu.
Explanation:
5 trial, had an average destiny of 7.40. g/cm
Polar Covalent.
This is because both Calcium (Ca) and Carbon (C) are non metals, thus eliminating the ionic option.
It is polar covalent rather than nonpolar covalent due to the fact that the electrons in a polar covalent bond are shared unequally while those in a nonpolar bond are shared equally.
This can be determined by looking at the amount of valence electrons; if the electrons cancel each other out, it is shared equally. If not, it is shared unequally.
Hope this helps!
Answer:
14
Explanation:
mass number = protons + neutrons
