Question

What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol∙K) 4.5 mol 0.18 mol 24.63 mol 5.47 mol 1.8 mol

Answer 1

P= 1.50 atm
V= 3 L
R= 0.08205 L∙atm/mol∙K
T= 300 K
n= ?

we all this information, we can tell that we need to use ideal gas formula

PV= nRT

if we rearrange the formula for n, we get--> n= PV/ RT

let's plug in the values. 

n= 1.5 x 3/ (0.08205 x 300)= 0.18 moles