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creativ13 [48]
3 years ago
12

What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol

∙K) 4.5 mol 0.18 mol 24.63 mol 5.47 mol 1.8 mol
Chemistry
1 answer:
Tomtit [17]3 years ago
3 0
P= 1.50 atm
V= 3 L
R= 0.08205<span> L∙atm/mol∙K
T= 300 K
n= ?

we all this information, we can tell that we need to use ideal gas formula

PV= nRT

if we rearrange the formula for n, we get--> n= PV/ RT

let's plug in the values. 

n= 1.5 x 3/ (0.08205 x 300)= 0.18 moles
</span>
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What type of chemical reaction is so3(g) + h2o(l) → h2so4(aq)?
Sloan [31]
Note: Above question is incomplete. Complete question is
<span>What type of chemical reaction is so3(g) + h2o(l) → h2so4(aq)
a) Neutralization
b) Decomposition
c) Combination
d) Single displacement reaction
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Solution:
In current context, following things may be noted
1) Neutralization reactions: In neutralization reactions, acid and base combine to form salt and water.
b) Decomposition reaction: R</span><span>eaction in which a single substance broken down two or more smaller substances is refereed as decomposition reaction. Decomposition reactions are characterized be present of single molecule on reactant side. 
c) Combination reaction: In a recombination reaction</span><span> two or more molecules combine to form a single product.
d) Single displacement reaction: R</span><span>eaction in which an element within a compound is displaced by a another element is referred as single displacement reaction. 

Above reaction satisfies the criteria of combination reaction, hence correct answer is option C, combination. </span>
3 0
3 years ago
Can anyone help with this?
8090 [49]
Yes what is it..we can help you
3 0
3 years ago
If 3.64g of sand is separated from 5.25g of a mixture of salt and sand what is the percentage of sand in the sample
Mashcka [7]
Total weight of the mixture of sand and salt = 5.25 g
Weight of sand separated = 3.64 g
Weight of the salt in the mixture = (5.25 - 3.64) g
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Then the percentage of sand in the sample = [(3.64/5.25) * 100] percent
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So the percentage of sand in the total mixture of sand and salt is 69.33%.
7 0
3 years ago
What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write
LuckyWell [14K]

The balanced chemical equation for reaction of AgNO_{3} and Na_{2}SO_{4} is as follows:

2 AgNO_{3}+Na_{2}SO_{4}\rightarrow 2NaNO_{3}+Ag_{2}SO_{4}

From the balanced chemical equation, 2 mol of AgNO_{3} reacts with 1 mol of  NaNO_{3}.

First calculating number of moles of NaNO_{3} as follows:

M=\frac{n}{V}

On rearranging,

n=M\times V

Here, M is molarity and V is volume. The molarity of NaNO_{3}  is given 0.274 M or mol/L and volume 155 mL, putting the values,

n=0.274 mol/L\times 155\times 10^{-3}mL=0.04247 mol

Since, 1 mol of NaNO_{3}  reacts with 2 mol of  AgNO_{3} thus, number of moles of  AgNO_{3}  will be 2\times 0.04247 mol=0.08494 mol.

Now, molarity of  AgNO_{3} is given 0.305 M or mol/L thus, volume can be calculated as follows:

V=\frac{n}{M}=\frac{0.08494 mol}{0.305 mol/L}=0.2785 L=278.5 mL

Therefore, volume of  AgNO_{3} is 278.5 mL.

4 0
4 years ago
What kind of data does regional climate mainly collect and concentrate on?
hram777 [196]

Answer:

Climate, atmosphere, and land

Explanation:

Some of the data collected include air chemistry, temperature, precipitation, cloud cover, and wind speed. Instruments carried on balloons and wind profiling radar provide observations from the surface to more than 10 miles high.

8 0
2 years ago
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