Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄ 
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Answer:
Distillation.
Explanation:
If we are heating a mixture of two miscible liquids and collecting the vapors it means we are separating the two mixtures from each other based on their boiling point differences.
This technique of separation of two liquids based on the difference in boiling point is known as Distillation.
Alcohol will evaporate easily as compared to water as water has stronger influence of hydrogen bond making the inter-molecular forces stronger.
Answer:
What is the question? I don't understand what you are trying to say.