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geniusboy [140]
2 years ago
6

Find the y-intercept of the equation. y=-3•7^x​

Mathematics
2 answers:
Lorico [155]2 years ago
7 0

Answer:

The y intercept is (0,-3)

12345 [234]2 years ago
5 0

Answer:

- 3

Step-by-step explanation:

To find the y- intercept set x equal to zero, that is

y = - 3 × 7^{0} = - 3 × 1 = - 3 ← y- intercept

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What is the answer for this equation or problem? y+6=52 and what does y equal.
Cloud [144]

Answer: y=46

Step-by-step explanation:

Subtract 6 from either side to ensure that the y is alone. This then equals y=52-6.

52-6= 46

So therefore, y=46

4 0
3 years ago
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If the perimeters of each shape are equal, which equation can be used to find the value of x? A triangle with base x + 2, height
Tju [1.3M]

Correct question :

If the perimeters of each shape are equal, which equation can be used to find the value of x? A triangle with base x + 2, height x, and side length x + 4. A rectangle with length of x + 3 and width of one-half x. (x + 4) + x + (x + 2) = one-half x + (x + 3) (x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3) 2 (x) + 2 (x + 2) = 2 (one-half x) + 2 (x + 3) x + (x + 2) + (x + 4) = 2 (x + 3 and one-half)

Answer: (x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3)

Step-by-step explanation:

Given the following :

A triangle with base x + 2, height x, and side length x + 4 - - - -

b = x + 2 ; a = x ; c = x + 4

Perimeter (P) of a triangle :

P = a + b + c

P =( x + 2) + x + (x + 4) - - - (1)

A rectangle with length of x + 3 and width of one-half x

l = x + 3 ; w = 1/2 x

Perimeter of a rectangle (P) = 2(l+w)

P = 2(x+3) + 2(1/2x)

If perimeter of each same are the same ; then;

(1) = (2)

(x + 2) + x + (x + 4) = 2(x+3) + 2(1/2x)

7 0
3 years ago
(05.03 LC) What is the initial value of the function represented by this graph? (1 point) ​
Liula [17]

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0

Step-by-step explanation:

8 0
2 years ago
Classify the solid.<br> PLS HELPP
Kruka [31]
Trapezoidal Prism

It is a prism with 2 bases of shape trapezoid
7 0
3 years ago
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Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n:
Klio2033 [76]

Answer: D

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

Counting which numbers are divisible by 16=2⁴:

16,32,48,...,96: 6 numbers (100/16=6.25 ==> 6)

Counting which numbers are divisible by 32=2⁵:

32,64,96 : 3 numbers(100/32=3.125 ==>3)

Counting which numbers are divisible by 64=2⁶:

64 : 1 number (100/64=1.5625 ==>1)

Sum of those numbers= 50+25+12+6+3+1=97

100! is divisible by 2⁹⁷.

Answer D

4 0
2 years ago
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