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ahrayia [7]
3 years ago
9

A sequential circuit has two inputs, w1and w2, and an output, z. Its function is to compare the input sequences on the two input

s. If w1= w2 during any three consecutive clock cycles, the circuit produces z= 1; otherwise, z= 0. The output should be equal to 1 in the same clock cycle when the third occurrence of w1= w2 is detected.

Engineering
1 answer:
zavuch27 [327]3 years ago
5 0

Answer / Explanation

The question is incomplete. It can be found in search engines. However, kindly find the complete question below:

A sequential circuit has two inputs w1 and w2, and an output, z. Its function is to compare the

input sequences of the two inputs. If w1=w2 during any four consecutive clock cycles, the

circuit produces z=1; otherwise, z=0.

For example

w1:0110111000110

w2:1110101000111

z:0000100001110

Draw the state diagram using the minimum number of states.

Answer:

To properly answer this question, let us first define what a sequential circuit is, and input sequence.

To start with,a Sequential circuit can be defined or described as a type of circuit system used in the digital world most importantly in the digital theory of circuits. It is a type of circuit system whose output does not only depends on present values of input signals but also involves the sequence of one or more inputs and one or more outputs of the past whose realities are related.

Input sequence: This can be refereed to as the arranged pattern in which the data or values are imputed in the circuit.

If we now refer back to the question, we have

For grading each state:

+1 for each correct transition                     = 2 total per state

+2 for each correct output                         = 2 total per state

Total for every state                                    = 4

Where the Maximum is  4*5 = 20

Hence,

If more than 5 states are used, but the logic is correct: +10 for the entire answer

Full credits for any other possible solution using 5 states.

We should also understand that : input labeled of (w1 =w2), (w1 == w2), (w1 XOR w2), 00,11 and similar also OK

We should also understand that : The solution here uses more machine. You can also use mealy machine. For mealy  machine, only 4 states are enough. If you use 5 states we don’t deduct points.

So in summary,  X = w1 XOR w2

Kindly find the required diagram below for proper clarity and understanding of the question.

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Answer:

Explanation:

From the given information:

Addition of all the materials = 65+ 36+ 5 +6 = 112  which is higher than 100 percentage; SO we need to find;

The actual percentage of each material which can be determined as follows:

Percentage of the coarse aggregate will be = 65 × 112/100

= 72.80%

Percentage of the Fine aggregate will be = 36 × 112/100

= 40.32%

Percentage of the filler  will be = 5 × 112/100

= 5.6%

Percentage of the   asphalt binder will be = 6 × 112/100

= 6.72 %

So; the theoretical specific gravity (Gt) of the mixture can be calculated as follows:

Gt = 100/( 72.80/2.635 + 40.32/2.710 + 5.6/2.748 + 6.72/1.088)

Gt = 100/( 27.628 + 14.878 + 2.039 + 6.177)

Gt = 100/ (50.722)

Gt =1.972

Also;Given that the bulk density = 143.9 lb/ft³

LIke-wsie ; as we know that unit weight of water is =62.43lb/cu.ft

Hence, the bulk specific gravity of the mix (Gm) = 143.9/62.43

=2.305

The percentage of air  void  = (Gt -Gm )× 100/ Gt

= (1.972 - 2.305) ×  100/ 1.972

= -16.89%

The percentage of the asphalt binder is =(6.72/1.088*100)/(72.80+40.32+5.6+6.72)/2.305)

= 617.647/54.42

= 11.35%

Thus; the percentage voids in mineral aggregate =  -16.89% + 11.35%

the percentage voids in mineral aggregate = -5.45%

The percent voids filled with asphalt. = 100 × 11.35/-5.45

The percent voids filled with asphalt = - 208.26 %

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3 years ago
A steam power plant operates on a simple ideal Rankine cycle between the pressure limits of 3000 kPa and 25 kPa. The temperature
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Answer:

a)31%

b)34MW

Explanation:

A rankine cycle is a generation cycle using water as a working fluid, when heat enters the boiler the water undergoes a series of changes in state and energy until generating power through the turbine.

This cycle is composed of four main components, the boiler, the pump, the turbine and the condenser as shown in the attached image

To solve any problem regarding the rankine cycle, enthalpies in all states must be calculated using the thermodynamic tables and taking into account the following.

• The pressure of state 1 and 4 are equal

• The pressure of state 2 and 3 are equal

• State 1 is superheated steam

• State 2 is in saturation state

• State 3 is saturated liquid at the lowest pressure

• State 4 is equal to state 3 because the work of the pump is negligible.

Once all enthalpies are found, the following equations are used using the first law of thermodynamics

Wout = m (h1-h2)

Qin = m (h1-h4)

Win = m (h4-h3)

Qout = m (h2-h1)

The efficiency is calculated as the power obtained on the heat that enters

Efficiency = Wout / Qin

Efficiency = (h1-h2) / (h1-h4)

For this problem, we will first find the enthalpies in all states

h1=3231kJ/Kg

h2=2310kJ/Kg

h3=h4=272kJ/Kg

A) using the eficiency ecuation

Efficiency = (h1-h2) / (h1-h4)

Efficiency =(3231-2310)/(3231-272)=0.31=<u>31%</u>

b)using ecuation for Wout

Wout = m (h1-h2)

Wout=37(3231-2310)=34077KW=<u>34.077MW</u>

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Answer:

2.6 miles

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Answer: c.An accumulator is not used in a system with a receiver/dryer

Explanation:

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Then, the refrigerant then condenses to liquid when the hear has been transferred.

We should note that the condenser is normally mounted in front of the radiator. The receiver/dryer is a storage tank for the liquid refrigerant from the condenser.

The statement that an accumulator is not used in a system with a receiver/dryer is not true. This is because, the accumulator gives protection to the compressor which helps to prevent the failure of the compressor.

Therefore, the answer is C.

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