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Oxana [17]
3 years ago
6

What energy type is represented in the picture?

Engineering
2 answers:
Kobotan [32]3 years ago
5 0
You got it correct! It would be considered Elastic.
9966 [12]3 years ago
4 0
It’s elastic energy
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Which term refers to the practical applications of scientific knowledge
xz_007 [3.2K]

Answer:

Technology

Explanation:

Technology is defined as the application of scientific knowledge for practical purposes, especially in industry . Sometimes applying scientific knowledge means using less of what we traditionally think of as technology.

7 0
3 years ago
A relatively nonvolatile hydrocarbon oil contains 4.0 mol % propane and is being stripped by direct superheated steam in a strip
hram777 [196]

Answer:

Number of Trays = Six (6)

Explanation:

Given that: y' = 25x' , in terms of molecular ratio, we can write it as

\frac{Y'}{1 + Y'} =25 \frac{X'}{1 + X'}  ......... 1

after plotting this we get equilibrium curve as shown in the attached picture.

inlet concentration and outlet concentration of liquid phase is

x₂ = 4% = 0.04 (inlet)

so that can be converted into molar

X_2 = \frac{x_2}{1-x_2} = \frac{0.04}{1-0.04} = 0.04167

and

x₁ = 0.2% = 0.002

X_1 = \frac{x_1}{1-x_1} = \frac{0.002}{1-0.002} = 2.004*10^{-3}

Now we have to use the balance equation a

\frac{G_s}{L_s} = \frac{X_2-X_1}{Y_2-Y_1} .............. a

here amount of solute is comparably lower than

Here we have

L = 300 kmol (total)

L_s = 300(1 - 0.04) = 288 kmol pure oil

G = G_s = 11.42 kmol

Y_1 = 0 , solvent free steam

substitute into the equation a

\frac{11.42}{288} = \frac{0.04167 - 2*10^{-3}}{Y_2 - 0}

Y₂ = 1.0003

Now plot the point A(X₁ , Y₁) and B(X₂ , Y₂) and join them to construct operating line AB.

Starting from point B, stretch horizontal line up to equilibrium curve and from there again go down to operating line as shown in the picture attached. This procedure give one count of tray and continue the same procedure up to end of operating.

at last count, the number of stage, gives 6.

∴ <em>Number of trays = 6</em>

5 0
4 years ago
Read 2 more answers
Question 1 : Replacement [42 Pts] Consider the following page reference string:
MakcuM [25]

Answer:

Optimal

Time 123456789101112

RS. ecbeagdcegda

F0. eeeeeeeee e e a

F1 c c c c c c c c c c c

F2 b b b g g g g g g g

F3 a a d d d d d d

Page fault? * * * * * * *

Total page fault:7

2. LRU

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 e e e e e e e c c c c a

F1 c c c c g g g g g g g

F2 b b b b d d d d d d

F3 a a a a e e e e

Page fault? Y Y Y N Y Y Y Y Y N N Y Total page fault:9

3. LRU approximation algorithm: Second chance

Time 1 2 3 4 5 6 7 8 9 10 11 12

RS e c b e a g d c e g d a

F0 0,e 0,e 0,e 1,e 1,e 0,e 0,e 0,e 1,e 1,e 1,e 0,e

F1 0,c 0,c 0,c 0,c 0,g 0,g 0,g 0,g 1,g 1,g 0,g

F20,b0,b0,b0,b0,d0,d0,d0,d1,d0,dF30,a0,a0,a0,c0,c0,c0,c0,a

Page fault? YYYNYYYYNNNY

Total page fault: 8

4 0
3 years ago
Read 2 more answers
The telescoping arm ABC is used to provide an elevated platform for construction workers. The workers and the platform together
Tasya [4]

Answer:

That is not a question...

4 0
2 years ago
A single lane highway has a horizontal curve. The curve has a super elevation of 4% and a design speed of 45 mph. The PC station
andreyandreev [35.5K]

Answer: 112 + 19.27

Explanation:

Super elevation is an inward transverse slope provided through out the length of the horizontal curve which ends up serving as a counteract to the centrifugal force and checks tendency of overturning. It changes from infinite radius to radius of a transition curve.

Super curve elevation (e) = 4%

4/100= 0.04

e= V^2/gR

Make R the subject of the formula.

egR= V^2

R= V^2/eg

V= 45mph

=45 × 0.44704m/s

=20.1168m/s

g (force due to gravity) =9.81

Therefore,

R= (20.1168)^2/9.81 × 0.04

= 1031.31m

Tangent Length( T) = PI - PC

Tangent Length= 10875 - 10500

=375m

T= R Tan(I/2)

375= 1031.31 × Tan(I/2)

I= 39.96

Also,

L= πRI/180

= 719.27m

Station PT= Stat PC+ L

10500 + 719.27

=11219.27

=112 + 19.27

6 0
3 years ago
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