In △XYZ , XZ=11 , YZ=8 , and m∠Z=31∘ .
1 answer:
Answer:
The area of the triangle is 22.7 units²
Step-by-step explanation:
The formula of the area of a triangle using trigonometry is A = (a)(b) sin(C), where a , b are two sides in the triangle and C is the angle between these two sides
In Δ XYZ
∵ XZ = 11 units
∵ YZ = 8 units
∵ m∠Z = 31°
∵ ∠Z is between the two sides XZ and YZ
∴ We can use the formula above to find the area of Δ XYZ
∵ Area Δ XYZ = (XZ)(YZ) sin(Z)
∴ Area Δ XYZ = (11)(8) sin(31)
∴ Area Δ XYZ = 22.6616753 unit²
- Round it to the nearest tenth
∴ Area Δ XYZ = 22.7 units²
The area of the triangle is 22.7 units²
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Answer:
No positive value of n
Step-by-step explanation:
we have to find out for how many positive values of n are both
our-digit integers
Let us consider first cube
we get 4digit lowest number is 1000 and it has cube root as 10.
Thus 10 is the least integer which satisfies four digits for cube.
The highest integer is 9999 and it has cube root as 21.54
or 21 the highest integer.
Considering 3^n we get,
3^10 is having 5 digits and also 3^21
Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.