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2 years ago

How do u do this please

Mathematics

1 answer:

blagie [28]2 years ago

4 0

Answer: In number 1 the answer is 2. Number 2 the answer is 7. Number 3 you read the problem as 4 x 4 x 4 or 4 to the 3rd. For number 4 it's 2x2x2x2x2x2x2 or 2 to the 7th power. Number 5 is right. For number 6 B. is 5. C is 6

Hope this helps

Step-by-step explanation:

You might be interested in

Evaluate each expression if a = 4.1, b = 5.7, and c=0.3.<br> 4. a+b-c <br> 5. 10-(a+b)<br> 6. B- c+2

posledela

Answer:

a+b-c = 9.5

10-(a+b) = 0.2

b-c+2 = 7.4

Step-by-step explanation:

Given the expression

a+b-c

a=4.1

b=5.7

c=0.3

substituting the values in the expression

a+b-c = 4.1+5.7-0.3

= 9.8 - 0.3

= 9.5

Given the expression

10-(a+b)

a=4.1

b=5.7

c=0.3

substituting the values in the expression

10-(a+b) = 10 - (4.1+5.7)

= 10 - 9.8

= 0.2

Given the expression

b-c+2

a=4.1

b=5.7

c=0.3

substituting the values in the expression

b-c+2 = 5.7 - 0.3 +2

= 5.4 + 2

= 7.4

7 0

2 years ago

I will give brainliest if this is answerd in 10 min it is timed here it is:this is worth 100 pts

Jobisdone [24]

Answer:

customary system:

miles

ounces

metric system:

deciliters

kilometers

centigram

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The area of Banff National Park is

vova2212 [387]

Answer:

ehheheheyeyr

ebehejeu

ehueueueueue

8 0

3 years ago

18. A I-10 number cube is rolled. What is the conditional probability that the number rolled is less than 6, given that the numb

Romashka-Z-Leto [24]

Answer:

30% Probability

Step-by-step explanation: 3/10=0.3

6 0

3 years ago

(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim

aleksklad [387]

(i) Given that

$V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr$

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

$V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}$

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

$\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

Compute the integral:

$V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr$

$V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr$

$V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R$

$V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)$

$V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}$

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0

2 years ago