Answer: one solution x + 3 = 5 x = 2 no other other value for x is possible
No solution: (x + 3) = 2(x +3)
Infinitely many solutions: x+3 = 3 + x
Step-by-step explanation:
why (x + 3) = 2(x +3) has no solution. Can you solve?
x+3=2x+6 -x=3 x=-3 substute -3 for x
(-3)+ 3)= 2[(-3) +3]
-3+3 = -6 +3
0 = -3 False!
x+3 = 3 + x has infinitely many solutions. Substitute any number for x, and the equation is true (5)+3=3+(5) 8=8 . 11111+3 =3+11111 11114=11114
Answer:
The answer is (a, 0)
Step-by-step explanation:
It's correct.
The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).
If there are only two colors (let's say blue and red), here's what can happen:
sock #1 is blue
#2 is either blue or red. If blue, it matches #1 and you have a pair.
if red, go to #3
#3-either blue or red. If blue, matches #1. If red, matches #2.
OR sock #1 is red... then just reverse the colors. Basically, if you have three things that can only be in two groups, then even if two of them are different, the last one has to match one of them.
Answer:
it could be that x is 4 and y 3
Step-by-step explanation:
