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miss Akunina [59]
4 years ago
15

If a circuit contains a 12v battery and two 3 bulbs in series

Physics
1 answer:
Paha777 [63]4 years ago
6 0

If the resistance of each bulb is 3 ohms, and they are connected across the battery, then current will flow through them.

In series, the two 3-ohm bulbs will look like a single 6-ohm resistance.

      Current = (voltage) / (resistance)  =  (12v) / (6 ohms) = 2 Amperes.

The battery will need to deliver some power to the circuit.

       Power = (voltage) x (current) = (12v) x (2 Amperes)  =  24 watts .

Each bulb will dissipate 12 watts, in the form of light and heat.

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A 0.20 kg mass (m1) hangs vertically from a spring and an elongation of the spring of 9.50 cm (r1) is recorded. With a mass (m2)
kupik [55]

Answer:

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Explanation:

Step one:

given data

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Step two:

From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F

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2=0.095k-ka----------1

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10=0.12k-ka----------2

solving equation 1 and 2 simultaneously

 

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3 years ago
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