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3 years ago

How long does it take a car traveling at 50.7 mi/hr to travel to 655 miles?

Physics

2 answers:

NeX [460]3 years ago

7 0

Answer:

33,208.5 HRS

Explanation:

yuradex [85]3 years ago

6 0

Answer:

12.919 hours

Explanation:

655/50.7

=12.919132

mi/hr

=50.7 miles every hour

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Triss [41]

The acceleration of the boat is $2 m/s^2$ (eastward)

Explanation:

We can solve this problem by using Newton's second law, which states that:

F = ma (1)

where

F is the net force on a body

m is its mass

a is its acceleration

First of all, we have to find the net force acting on the boat. We have:

- The force of the motor, 100 N eastward

- The force of the air resistance, 60 N westward

So the net force is:

F = 100 N - 60 N = 40 N (eastward)

Now we can apply eq.(1), using:

F = 40 N

m = 20 kg (mass of the boat)

and solving for a, we find the acceleration:

$a=\frac{F}{m}=\frac{40}{20}=2.0 m/s^2$

And the direction is the same as the net force (eastward).

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3 years ago

11. A box with a mass of 1.0 kg is resting on a horizontal surface and the coefficient of friction between the block and the sur

AlladinOne [14]

Answer:

We know that the force pulling the box in the positive x direction has a magnitude of m g sin 30 . Using Newtons Second Law, F = ma , we just need to solve for a :

ma=mgsin30

a=gsin30

=(10m/s2)(0.500)

=5m/s2

5 0

2 years ago

Read 2 more answers

A fisherman has caught a very large, 5.0kg fish from a dock that is 2.0m above the water. He is using lightweightfishing line th

agasfer [191]

Answer:

t = 2 s

Explanation:

As we know that fish is pulled upwards with uniform maximum acceleration

then we will have

$T - mg = ma$

here we know that maximum possible acceleration of so that string will not break is given as

$T = 54 N$

now we have

$54 - (5 \times 9.8) = 5 a$

$a = 1 m/s^2$

now for such acceleration we can use kinematics

$d = \frac{1}{2}at^2$

$2 = \frac{1}{2}(1) t^2$

t = 2 s

7 0

3 years ago

You are driving your 1700 kg car at 21 m/s down a hill with a 5.0∘ slope when a deer suddenly jumps out onto the roadway. You sl

podryga [215]

Answer:

d = 27.7 m

Explanation:

Here the car is driving on the inclined plane

So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system

So here we can write it as

$mgsin\theta \times d - F_f \times d = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

now we have

m = 1700 kg

$v_f = 0$

$v_i = 21 m/s$

$F_f = 1.5 \times 10^4 N$

$(1700)(9.81)sin5 (d) - (1.5\times 10^4)d = 0 - \frac{1}{2}(1700)(21^2)$

$1453.5 d - (1.5\times 10^4)d = -374850$

$d = 27.7 m$

6 0

3 years ago

Ruby is out with her friends. Misfortune occurs and

zhannawk [14.2K]

The work done is $2.35\cdot 10^5 J$

Explanation:

The work done by a force on an object is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In this problem, we have

F = 1080 N is the force applied on the car

d = 218 m is the displacement of the car

And assuming the force is applied parallel to the motion of the car, $\theta=0^{\circ}$ , and so the work done is

$W=(1080)(218)(cos 0^{\circ})=2.35\cdot 10^5 J$

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2 years ago