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faltersainse [42]
3 years ago
8

How long does it take a car traveling at 50.7 mi/hr to travel to 655 miles?

Physics
2 answers:
NeX [460]3 years ago
7 0

Answer:

33,208.5 HRS

Explanation:

yuradex [85]3 years ago
6 0

Answer:

12.919 hours

Explanation:

655/50.7

=12.919132

mi/hr

=50.7 miles every hour

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Two identical satellites orbit the earth in stable orbits. one satellite orbits with a speed v at a distance r from the center o
wariber [46]
The available options are: (found the complete text on internet)
A- at a distance less than r
B- at a distance equal to r
C- at a distance greater than r

Solution:
The correct answer is C) at a distance greater than r.

In fact, the gravitational attraction between the satellite and the Earth provides the centripetal force that keeps the satellite in circular orbit, so we can write
G \frac{Mm}{r^2}=m \frac{v^2}{r}
where the term on the left is the gravitational force, while the term on the right is the centripetal force, and where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's center
v is the satellite speed

Re-arranging the equation, we get
r= \frac{GM}{v^2}
and we see from this formula that, if the second satellite has a speed less than the speed v of the first satellite, it means that the denominator of the fraction is smaller, and so r is larger for the second satellite.
7 0
3 years ago
State and prove bessel inequality​
maria [59]

Statement :- We assume the orthagonal sequence {{\{\phi\}}_{1}^{\infty}} in Hilbert space, now {\forall \sf \:v\in \mathbb{V}}, the Fourier coefficients are given by:

{\quad \qquad \longrightarrow \sf a_{i}=(v,{\phi}_{i})}

Then Bessel's inequality give us:

{\boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}

Proof :- We assume the following equation is true

{\quad \qquad \longrightarrow \displaystyle \sf v_{n}=\sum_{i=1}^{n}a_{i}{\phi}_{i}}

So that, {\bf v_n} is projection of {\bf v} onto the surface by the first {\bf n} of the {\bf \phi_{i}} . For any event, {\sf (v-v_{n})\perp v_{n}}

Now, by Pythagoras theorem:

{:\implies \quad \sf \Vert v\Vert^{2}=\Vert v-v_{n}\Vert^{2}+\Vert v_{n}\Vert^{2}}

{:\implies \quad \displaystyle \sf ||v||^{2}=\Vert v-v_{n}\Vert^{2}+\sum_{i=1}^{n}\vert a_{i}\vert^{2}}

Now, we can deduce that from the above equation that;

{:\implies \quad \displaystyle \sf \sum_{i=1}^{n}\vert a_{i}  \vert^{2}\leqslant \Vert v\Vert^{2}}

For {\sf n\to \infty}, we have

{:\implies \quad \boxed{\displaystyle \bf \sum_{1}^{\infty}\vert a_{i}\vert^{2}\leqslant \Vert v\Vert^{2}}}

Hence, Proved

5 0
2 years ago
Read 2 more answers
A motorcyclist drove 7 km at 57km/h and then another 7 km at 81 km/h. What was the average speed? ​
alex41 [277]

<u>Answer:</u>

<em>The average speed of the car is 66.9 km/h</em>

<u>Explanation:</u>

Here distance covered with the speed <em>57 km/h=7 km  </em>

distance covered with the speed of <em>81 km/h=7 km</em>

<em>Average speed is equal to the ratio of total distance to the total time. </em>

<em>total distance= 7 + 7= 14 km  </em>

<em>time= \frac{distance}{speed} </em>

<em>time taken to cover the first 7 km= 7/57 h  </em>

<em>time taken to cover the second part of the journey = 7/81 h </em>

<em>average speed =  14/(7/57+7/81)=(14 \times 57 \times 81)/945=66.9 km/h</em>

<u><em>Shortcut: </em></u>

<em>When equal distances are covered with different speeds average speed=2 ab/(a+b) where a and b are the variable speeds in the phases. </em>

7 0
3 years ago
After a plant or animal dies the 14C content decreases with a half-life of 5730 years. If an archaeologist finds an ancient fire
Shalnov [3]

Answer:

age of the site is 15411.75 years old

Explanation:

Given data

plant or animal dies = 14C

time period = 5730 year

carbon = 15.5%

to find out

age (in years) of the ancient site

solution

we know that Final value = Initial value  × 0.5^{n}

here n is half life passed

so for 15.5%

15.5% = 100% of  0.5^{n}

0.155 = 1 × 0.5^{n}

now take log both side

log 0.155 = log  0.5^{n}

n = log 0.155 / log 0.5

n = 2.68966

we know here  5730 years in half life

so for 2.68966 half-lives = 2.68966 × 5730  =  15411.7518

age of the site is 15411.75 years old

6 0
3 years ago
1. What do you mean by energy ?
sammy [17]

Answer:

<em><u>1</u></em><em><u>.</u></em><em><u> </u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>a</u></em><em><u>b</u></em><em><u>i</u></em><em><u>l</u></em><em><u>i</u></em><em><u>t</u></em><em><u>y</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>b</u></em><em><u>o</u></em><em><u>d</u></em><em><u>y</u></em><em><u> </u></em><em><u>t</u></em><em><u>o</u></em><em><u> </u></em><em><u>d</u></em><em><u>o</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>w</u></em><em><u>o</u></em><em><u>r</u></em><em><u>k</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>c</u></em><em><u>a</u></em><em><u>l</u></em><em><u>l</u></em><em><u>e</u></em><em><u>d</u></em><em><u> </u></em><em><u>e</u></em><em><u>n</u></em><em><u>e</u></em><em><u>r</u></em><em><u>g</u></em><em><u>y</u></em><em><u>.</u></em><em><u> </u></em>

<em><u>2</u></em><em><u>.</u></em><em><u> </u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>S</u></em><em><u>.</u></em><em><u>I</u></em><em><u>.</u></em><em><u> </u></em><em><u>u</u></em><em><u>n</u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>e</u></em><em><u>n</u></em><em><u>e</u></em><em><u>r</u></em><em><u>g</u></em><em><u>y</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>j</u></em><em><u>o</u></em><em><u>u</u></em><em><u>l</u></em><em><u>e</u></em><em><u>(</u></em><em><u>J</u></em><em><u>)</u></em><em><u>.</u></em>

<em><u>3</u></em><em><u>.</u></em><em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>d</u></em><em><u>i</u></em><em><u>f</u></em><em><u>f</u></em><em><u>e</u></em><em><u>r</u></em><em><u>e</u></em><em><u>n</u></em><em><u>t</u></em><em><u> </u></em><em><u>t</u></em><em><u>y</u></em><em><u>p</u></em><em><u>e</u></em><em><u>s</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>e</u></em><em><u>n</u></em><em><u>e</u></em><em><u>r</u></em><em><u>g</u></em><em><u>y</u></em><em><u> </u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>:</u></em>

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  • <em><u>M</u></em><em><u>a</u></em><em><u>g</u></em><em><u>n</u></em><em><u>e</u></em><em><u>t</u></em><em><u>i</u></em><em><u>c</u></em><em><u> </u></em><em><u>E</u></em><em><u>n</u></em><em><u>e</u></em><em><u>r</u></em><em><u>g</u></em><em><u>y</u></em><em><u> </u></em>
  • <em><u>C</u></em><em><u>h</u></em><em><u>e</u></em><em><u>m</u></em><em><u>i</u></em><em><u>c</u></em><em><u>a</u></em><em><u>l</u></em><em><u> </u></em><em><u>E</u></em><em><u>n</u></em><em><u>e</u></em><em><u>r</u></em><em><u>g</u></em><em><u>y</u></em><em><u> </u></em>
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Explanation:

<h3 /><h3><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>w</u></em><em><u>o</u></em><em><u>r</u></em><em><u>k</u></em><em><u>s</u></em><em><u> </u></em><em><u>o</u></em><em><u>u</u></em><em><u>t</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em></h3>
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3 years ago
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