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2 years ago

14

What happens to the force between two charges if the magnitude of both charges is doubled and the distance between them is doubl

ed

1 answer:

vlabodo [156]2 years ago

4 0

Answer:the force will remain same

Explanation:

because force is equal to the ratio of magnitude and distance

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A person's speed around the Earth is faster at the poles than it is at the equator.

VashaNatasha [74]

Answer:

no

Explanation:

it is faster at the equator

6 0

2 years ago

In this graph, what is the displacement of the particle in the last two seconds?

nikklg [1K]

In this graph, what is the displacement of the particle in the last two seconds?of the particle in the last two seconds?

<span>0.2 meters
2 meters
4 meters
6 meters</span>
In this graph, the displacement of the particle in the last two seconds is 2 meters.

7 0

3 years ago

A playground slide is in the form of an arc of a circle with a maximum height of 3.0 m, with a radius of 8.5 m, and with the gro

julia-pushkina [17]

Answer:

a) $s \approx 6.676\,m$

Explanation:

a) Let assume that the ground is not inclined, since the bottom of the playground slide is tangent to ground. Then, the length of given by the definition of a circular arc:

$s = \frac{\pi}{4}\cdot R$

$s=\frac{\pi}{4}\cdot (8.5\,m)$

$s \approx 6.676\,m$

The bottom of the slide has a height of zero. The physical phenomenon around Dr. Ritchey's daughter is modelled after Principle of Energy Conservation. The child begins at rest:

$U_{g,A} = K_{B} + W_{fr}$

$m\cdot g \cdot h_{A} = \frac{1}{2}\cdot m \cdot v_{B}^{2} + f\cdot s$

The average frictional force is cleared within the expression:

$f = \frac{m\cdot (g\cdot h_{A}-\frac{1}{2}\cdot v_{B}^{2})}{s}$

$f = \frac{(12\,kg)\cdot [(9.807\,\frac{m}{s^{2}} )\cdot (3\,m)-\frac{1}{2}\cdot (4.5\,\frac{m}{s} )^{2} ]}{6.676\,m}$

$f = 34.684\,N$

4 0

2 years ago

An object is placed to the left of a convex mirror, such that the object-to-image distance is 140 cm.

labwork [276]

Answer:

The focal length of the mirror is 52.5 cm.

Explanation:

Given that,

Object to Image distance d = 140 cm

Image distance v= 35 cm

We need to calculate the object distance

$u = d-v$

$u = 140-35=105\ cm$

We need to calculate the focal length

Using formula of mirror

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}$

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{-105}+\dfrac{1}{35}$

$\dfrac{1}{f}=\dfrac{2}{105}$

$f=52.5\ cm$

Hence, The focal length of the mirror is 52.5 cm.

6 0

3 years ago

A tiger runs one kilometer. The tiger does 15,000 J of work and has a total power output of 500 W. How many minutes does it take

defon

Power is the amount of energy consumed per unit time. Having no direction, it is a scalar quantity. <span>As is implied by the equation for </span>power<span>, a unit of </span>power <span>is equivalent to a unit of work divided by a unit of time. The formula would be as follows:

P = W/t

We calculate as follows:

500 W = 15000 J / t
t = 30 s</span>

3 0

2 years ago