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kherson [118]
2 years ago
14

What happens to the force between two charges if the magnitude of both charges is doubled and the distance between them is doubl

ed
Physics
1 answer:
vlabodo [156]2 years ago
4 0

Answer:the force will remain same

Explanation:

because force is equal to the ratio of magnitude and distance

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I need help with #40 need answer and show me what you multiplied please
ale4655 [162]
(0.5)×(0squared)×(3)=(1.5j)
3 0
2 years ago
A beam of light has a wavelength of 650 nm in vacuum. (a) What is the speed of this light in a liquid whose index of refraction
Lady_Fox [76]

Answer:

The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

Explanation:

Given that,

Wavelength = 650 nm

Index refraction = 1.47

(a). We need to calculate the speed

Using formula of speed

n = \dfrac{c}{v}

Where, n = refraction index

c = speed of light in vacuum

v = speed of light in medium

Put the value into the formula

1.47=\dfrac{3\times10^{8}}{v}

v=\dfrac{3\times10^{8}}{1.47}

v= 2.04\times10^{8}\ m/s

(b). We need to calculate the wavelength

Using formula of wavelength

n=\dfrac{\lambda_{0}}{\lambda}

\lambda=\dfrac{\lambda_{0}}{n}

Where, \lambda_{0} = wavelength in vacuum

\lambda = wavelength in medium

Put the value into the formula

\lambda=\dfrac{650\times10^{-9}}{1.47}

\lambda=442\times10^{-9}\ m

Hence, The speed of this light and wavelength in a liquid are 2.04\times10^{8}\ m/s and 442 nm.

3 0
3 years ago
An applied force varies with position according to F = k1 x n − k2, where n = 3, k1 = 3.6 N/m3 , and k2 = 76 N. How much work is
aniked [119]

Answer:

The work done is 205 kJ.

Explanation:

Hi there!

Work can be calculated using the following equation:

W = F · Δx

Where:

W = work

F = applied force

Δx = displacement

In this case, the force varies with the position, so we can divide the traveled distance in very small parts and calculate the work done over each part of the trajectory. Then, we have to sum all the works and we will obtain the work done from the initial position (xi) to the final position (xf). This is the same as saying:

W = ∫ F · dx  

F = 3.6 N/m³ · x³ - 76 N

W = ∫ (3.6 x³ - 76)dx

W = 0.9 x⁴ - 76x

Evaluating from xi to xf:

W = 0.9 N/m³ (21.9 m)⁴ - 76 N · 21.9 m - 0.9 N/m³(5.41 m)⁴ + 76 N · 5.41 m

W = 205 kJ

8 0
3 years ago
We know velocity of sound v=a₩(omega), but speed does not depend on amplitude, why?
MrRissso [65]
Hope it helps............

8 0
3 years ago
What is its maximum altitude above the ground? The answer is the maximum height above the ground
Kisachek [45]

Answer:

Maximum altitude above the ground = 1,540,224 m = 1540.2 km

Explanation:

Using the equations of motion

u = initial velocity of the projectile = 5.5 km/s = 5500 m/s

v = final velocity of the projectile at maximum height reached = 0 m/s

g = acceleration due to gravity = (GM/R²) (from the gravitational law)

g = (6.674 × 10⁻¹¹ × 5.97 × 10²⁴)/(6370000²)

g = -9.82 m/s² (minus because of the direction in which it is directed)

y = vertical distance covered by the projectile = ?

v² = u² + 2gy

0² = 5500² + 2(-9.82)(y)

19.64y = 5500²

y = 1,540,224 m = 1540.2 km

Hope this Helps!!!

3 0
3 years ago
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