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ziro4ka [17]
3 years ago
13

a sample of ammonia liberates 5.66 kj as it solidifies at its melting point. what is the mass of the sample?

Chemistry
1 answer:
umka21 [38]3 years ago
8 0
The mass of the sample is 17.031.

The mass of a substance don't change. Ammonia or NH3 is a compound of Nitrogen and Hydrogen. Ammonia is classified as a gas.  In this compound, nitrogen has an atomic mass of 14 and hydrogen has 1 and multiply by three therefore the sum of their mass is 17.
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Elemental sulfur is one of the products of the gas-phase reaction of nitric acid and hydrogen sulfide. The other
Goshia [24]

Answer:

The manufacturing processes for liquefied petroleum gas are designed so that the majority, if not all, of the sulfur compounds are removed. The total sulfur level is therefore considerably lower than for other crude oil-based fuels and a maximum limit for sulfur content helps to define the product more completely. The sulfur compounds that are mainly responsible for corrosion are hydrogen sulfide, carbonyl sulfide and, sometimes, elemental sulfur. Hydrogen sulfide and mercaptans have distinctive unpleasant odors. A control of the total sulfur content, hydrogen sulfide and mercaptans ensures that the product is not corrosive or nauseating. Stipulating a satisfactory copper strip test further ensures the control of the corrosion.

8 0
3 years ago
A gas in a piston–cylinder assembly undergoes a compression process for which the relation between pressure and volume is given
m_a_m_a [10]

Answer:

1.

A=69.8\frac{bar}{m^6}\\\\ B=0.00302bar*m^6

2. W=-8.2kPa

Explanation:

Hello,

1. In this case, for the given p-V equation, one could use the two states to form a 2x2 linear system of equations in terms of A and B:

\left \{ {{0.1^2A+0.1^{-2}B=1} \atop {0.04^2A+0.04^{-2}B=2}} \right.

\left \{ {{0.01A+100B=1} \atop {0.0016A+625B=2}} \right

Whose solution by any method for solving 2x2 linear system of equations (elimination, reduction or substitution) is:

A=69.8\frac{bar}{m^6}\\\\ B=0.00302bar*m^6

2. Now, for us to compute the work, we must first compute n, as the power relating the pressure and volume for this process:

P_1V_1^n=P_2V_2^n\\\\\frac{P_1}{P_2}=(\frac{V_2}{V_1}  )^n\\\\\frac{1bar}{2bar}= (\frac{0.04m^3}{0.1m^3}  )^n\\\\0.5=0.4^n\\\\n=\frac{ln(0.5)}{ln(0.4)} =0.7565

Now, we compute the work:

W=\frac{P_2V_2-P_1V_1}{1-n} =\frac{2bar*0.04m^3-1bar*0.1m^3}{1-0.7565} \\\\W=-0.082bar*m^3*\frac{1x10^2kPa}{1bar}\\ \\W=-8.2kPa

Regards.

8 0
3 years ago
When an experiment is repeated and the new results are different from the original results, what could you assume to be true?
goldenfox [79]

Answer:

C since however many times you repeat an experiment, it should give the exact same results or it wouldn't be accurate enough. ex if you measure a liquid to be 77ml in USA, it should give the same when measured in Germany, same with repeating experiments.

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Read 2 more answers
Can we create matter? Why or why not?
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Answer:

The first law of thermodynamics doesn't actually specify that matter can neither be created nor destroyed So yes we can create matter because matter is every where buildings ,structures etc. So the answer is yes!

Explanation:

 

                         Hope this helped!ヾ(•ω•`)o❤

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First: the coefficients give the number of molecules (or atoms) involved in the reaction. In the example reaction, two molecules of hydrogen react with one molecule of oxygen and produce two molecules of water. Second: the coefficients give the number of moles of each substance involved in the reaction.

4 0
4 years ago
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