C2H6O + 3 O2 = 2 CO2 + 3 H2O.
Answer:
no se pero gana pls PorFAVORRRRRR.... DOXEADO TU IP 19503236
1. true, more effective collisions per second. Faster reaction
2. <span>How can the reaction be slowed down? (talking about how fast or slow the reaction is)
</span>3. True
4. Rate lower if surface area decrease
5. Fine powder form
6. True
7. False
Image questions:
1. False
2. Energy of reactants higher than products.
Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know, ![pK_a = -log\ K_a](https://tex.z-dn.net/?f=pK_a%20%3D%20-log%5C%20%20K_a)
Taking antilog both side, we get :
![K_a = 1.78\times 10^{-5}](https://tex.z-dn.net/?f=K_a%20%3D%201.78%5Ctimes%2010%5E%7B-5%7D)
Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :
![\alpha = \sqrt{\dfrac{K_a}{C}}\\\\\alpha =\sqrt{ \dfrac{1.78\times 10^{-5}}{0.1}}\\\\\alpha = 0.0133\times 100 = 1.33 \%](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Csqrt%7B%5Cdfrac%7BK_a%7D%7BC%7D%7D%5C%5C%5C%5C%5Calpha%20%3D%5Csqrt%7B%20%5Cdfrac%7B1.78%5Ctimes%2010%5E%7B-5%7D%7D%7B0.1%7D%7D%5C%5C%5C%5C%5Calpha%20%3D%20%090.0133%5Ctimes%20100%20%3D%201.33%20%5C%25)
Hence, this is the required solution.