Answer is <span>
Ni²</span>⁺(aq)
+ 6NH₃(aq)
⇌ [Ni(NH₃)₆]²⁺<span>
</span>
<span>When the concentration of Ni²⁺</span><span>(aq) increases, according to the Le Chatelier’s principle
system tries to become equilibrium by reducing the increased factor. To do
that, the concentration of Ni²⁺</span><span>(aq) should be reduced. Hence, the forward reacted should be
promoted to reduce the Ni²⁺</span><span>(aq) concentration</span>.
I'm going to suppose you want the adjusted chemical reaction, using the formulas of the compounds. You can see it in the image attached.
Answer:
The answer to your question is the letter d. S
Explanation:
Data
Change of +4 in the oxidation number
Chemical reaction
K₂Cr₂O₇ + H₂O + S ⇒ KOH + Cr₂O₃ + SO₂
Process
1.- Calculate the oxidation numbers following the rules.
Some rules
H = +1 O = -2 Alkali metals = + 1 Alkali earth metals = +2
K₂⁺¹Cr₂⁺⁶O₇⁻² + H₂⁺¹O⁻² + S⁰ ⇒ K⁺¹O⁻²H⁺¹ + Cr₂⁺³O₃⁻² + S⁺⁴O₂⁻²
Elements that changed their oxidation numbers
Cr₂⁺⁶ ---------------- Cr₂⁺³
S⁰ --------------- S⁺⁴
Answer:
C. NaOH(s) + HCl(aaq) rightarrow NaCl(s) + H2O(aq)
Explanation:
A neutralization reaction may be defined as the reaction where an acid when it reacts with some base, the products formed are a salt and water.
Simply, we can write,
acid + base ---> salt + water
Here in option (C),
NaOH is sodium hydroxide is an base
HCl is hydrochloric acid
NaCl is sodium chloride and is the common salt
H20 is water
So, option C). NaOH(s) + HCl(aaq) -----> NaCl(s) + H2O(aq) is a neutralization reaction.
The mass of cobalt (III) needed is
m = 5.2 L (0.42 mol/L) ( 93 g/mol)
m = 97.65 g
The volume of nitric acid needed is
V = 5.2 L (0.42 mol/L) (3 mol / 1 mol) (1000 mL/1.6 mol)
V = 1968.75 mL
The moles of water produced is
n = 5.2 L (0.42 mol/L) (3 mol / 1 mol)
n = 3.15 moles
