Two equations are given in the quastion and there are two unknown variables "x" and "y" in them. So solving will not be an issue at all. Taking the first equation: 5x + 2y = 16 2y = 16 - 5x y = 8 - (5x/2) Now putting the value of x found from the first equation in the second equation, we get -4x + 3y = -2 -4x + 3(8 - 5x/2) = -2 -4x + 24 - 15x/2 = -2 -8x + 48 -15x = -4 -23x = -4 - 48 -23x = -52 x = 52/23 Now putting the value of x in the first equation we get 5x + 2y = 16 5(52/23) + 2y = 16 260/23 + 2y = 16 260 + 46y = 368 46y = 368 - 260 46y = 108 y = 108/46 = 54/23 So the value of x is 52/23 and the value of y is 54/23
2(4+2x)≥5x+5 4+2x≥5/2x+5/2 (divide both sides by 2) 3/2+2x≥5/2x (subtract 5/2 from both sides) 3/2≥1/2x (subtract 2x from both sides) 3≥x (multiply both sides by 2) or x≤3
