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mestny [16]
3 years ago
5

Consider two solutions: solution x has a ph of 4; solution y has a ph of 7. from this information, we can reasonably conclude th

at _____
Chemistry
1 answer:
KIM [24]3 years ago
3 0
<span>Consider two solutions: solution X has a pH of 4; solution Y has a pH of 7. From this information, we can reasonably conclude that </span>the concentration of hydrogen ions (H⁺) or hydronium ions (H₃O⁺) in solution X is thousand times as great as the concentration of hydrogen ions or hydronium ions in solution Y.
Solution X: c(H⁺) = 10∧-pH = 10⁻⁴ mol/L = 0,0001 mol/L.
Solution Y: c(H⁺) = 10⁻⁷ mol/L = 0,0000001 mol/L.
0,0001 mol/L / 0,0000001 mol/L = 1000.

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What mass of lithium phosphate would you mass to make 2.5 liter of 1.06 M lithium
alex41 [277]

Answer:

Approximately 3.06 \times 10^{2}\; \rm g (approximately 306\; \rm g.)

Explanation:

Calculate the quantity n of lithium phosphate in V = 2.5\; \rm L of thisc = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1} lithium phosphate solution.

\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}.

Empirical formula of lithium phosphate: \rm Li_3PO_4.

Look up the relative atomic mass of \rm Li, \rm P,and \rm O on a modern periodic table:

  • \rm Li: 6.94.
  • \rm P: 30.974.
  • \rm O: 15.999.

Calculate the formula mass of \rm Li_3PO_4:

M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}.

Calculate the mass of that n = 2.65\; \rm mol of \rm Li_3PO_4 formula units:

\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}.

5 0
3 years ago
Which of the following ratios are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassiu
Zielflug [23.3K]

The ratios which are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassium chlorate are;

  • 31.998 g O2 : 1 mole O2
  • 3 mole O2 : 2 mole KClO3
  • 112.55 g KClO31 mole KClO3

From stoichiometry;

  • We can conclude that according to the reaction;

3 moles of oxygen requires 2 moles of KClO3 to be produced.

And from molar mass analysis;

  • 31.998 g O2 is equivalent to 1 mole O2
  • O2112.55 g KClO3 is equivalent to 1 mole KClO3

Read more:

brainly.com/question/9920155

7 0
3 years ago
Elements chemically combine in various ways to form most substances on Earth. These chemically combined elements are called ____
AleksAgata [21]

Answer:

compounds

Explanation:

the actual term would be chemical compound

3 0
2 years ago
Read 2 more answers
Aluminum (Al) is a/an:
Zinaida [17]

Answer:

Element.

Explanation:

Aluminum is an element because it is not separable into simpler substances. One thing important to keep in mind is that if something is on the Periodic Table of Elements, it is 100% an element.

8 0
3 years ago
What is the mole fraction of solute and the molal concentration for an aqueous solution that is 20.0% NaOH by mass?
never [62]
Let's assume we have 100 grams of this solution, and therefore 20.0 grams of NaOH, and 80.0 grams of water.

NaOH has a molar mass of 40.00 grams/mole, so we can convert NaOH to moles: (20.0 grams of NaOH) * (1 mole NaOH/40.00 grams NaOH) = 0.500 moles NaOH.

Next, we have a molar mass of water of 18.02 g/mol, so we can convert water to moles:

80.0 grams H2O * (1 mole H2O/18.02 grams) = 4.44 moles H2O
The mole fraction of NaOH is the moles of NaOH over the total moles of all parts of the solution. Therefore:

(0.500 moles NaOH)/(0.500 moles + 4.44 moles) = 0.101
0.101 = mole fraction of solute

The molal concentration is defined as the number of moles of solute over the number of kilograms of solvent (water).
We have 0.500 moles of NaOH, and 0.0800 kg of water, so it becomes:
(0.500 moles NaOH)/(0.0800 kg H2O solvent) = 6.25 molal solution
8 0
3 years ago
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