Find the moles of CaO
divide mass (2.0g) by the RFM which is 56 (Ca is 40 add that to O which is 16 making 56) this gives 0.0356 moles.
Find the theoretical mass by multiplying the moles of CaO (which is 0.0356 as there are no balancing number making the ratio 1:1) by the RFM of Ca(OH)2 which is 74 (40+16+16+1+1)
74 (Ca(OH)2 RFM) x 0.0357 (CaO moles) = 2.6g which is the theoretical mass of Ca(OH)2
Find percentage yield by dividing the actual mass of Ca(OH)2 by the theoretical and then x100 this Should give you 82.3%
Answer:
Is there a diagram that you can post
It was a Cambridge UK scientist in the early part of the 20 th century who discovered the electron. His name was J J Thompson.
Hey there!
Here is the answer to your question.
Answer : <em>4) The total number of electrons increases down the group, and this increases the strength of the intermolecular forces.</em>
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I hope this helps you! Let me know if you need anymore help on anything you are struggling with! ☺
Answer:
<em>Mass and size</em> are properties not commonly used to identify minerals.
