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DENIUS [597]
4 years ago
14

BRAINLIESTTT ASAP!!! PLEASE HELP ME :)

Chemistry
1 answer:
Anvisha [2.4K]4 years ago
6 0

Science and Pseudoscience. [email protected] is a prefix meaning A [email protected] or [email protected] Pseudoscience is fake science, a collection of assertions that do not satisfy the requirements and practices of true science. ... No natural phenomena or processes previously unknown to science have ever been discovered by pseudoscience. Hope this helps!

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4.93x10^25x(6.02 x 10^23)
Dmitriy789 [7]
The answer should be
2.96786*10^49
3 0
3 years ago
WHAT IS A ELECTROLYTE?THIS IS FOR MY PRESENTATION
Alexxx [7]

Answer:

Explanation:

substance (as an acid or salt) that when dissolved (as in water) conducts an electric current.

6 0
4 years ago
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given the following chemical equation, determine how many grams of N2 are produced by 9.24 of H2O2 nd 6.56g of N2H4
taurus [48]
I think the chemical reaction is:<span>

N2H4 + 2 H2O2-> N2 + 4H2O

We are given the amount reactants allowed to react. This will be the starting point of the reaction. First, is to find the limiting reactant.

9.24 g H2O2 ( 1 mol / 34.02 g ) = 0.27 mol H2O2
6.56  g N2H4 ( 1mol / 32.06) = 0.20 mol N2H4

Since from the reaction we have 1:2 ratio of the reactants then the limiting reactant is hydrogen peroxide. We will use this to find the amount of N2 produced.

0.27 mol H2O2 ( 1 mol N2 / 2 mol H2O2 ) ( 14.01 g N2 / 1 mol N2) =1.89 g N2 </span>
7 0
4 years ago
A gas has a volume of 62.65L at O degrees Celsius and 1 atm. At what temperature in Celsius would the volume of the gas be 78.31
Anastaziya [24]

Answer:

The volume of the gas will be 78.31 L at 1.7 °C.

Explanation:

We can find the temperature of the gas by the ideal gas law equation:

PV = nRT

Where:

n: is the number of moles

V: is the volume

T: is the temperature

R: is the gas constant = 0.082 L*atm/(K*mol)

From the initial we can find the number of moles:

n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles

Now, we can find the temperature with the final conditions:

T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K

The temperature in Celsius is:

T_{2} = 274.7 - 273 = 1.7 ^{\circ} C

Therefore, the volume of the gas will be 78.31 L at 1.7 °C.

I hope it helps you!            

8 0
3 years ago
Which determines the reactivity of an alkali metal?
adelina 88 [10]

Answer:

its ability to lose electron

3 0
3 years ago
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